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Bas_tet [7]
3 years ago
15

Rewrite the expression with a rational exponent as a radical expression

Mathematics
1 answer:
erica [24]3 years ago
8 0
I would say C so sorry if it’s not correct
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-8-x=x-4x < what is the answer Please show work. 37 POINTS
goldfiish [28.3K]

Answer:

-8-x=x-4x

-8-x=-3x

-8=-2x

4=x

7 0
3 years ago
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Which graph represents the solution for x2 + x - 12 > 0?
igomit [66]

Answer:it’s c on edge, sorry i’m late but for anyone else who needs help it’s c !!

Step-by-step explanation:

6 0
3 years ago
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Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a radius of 13 feet and
emmasim [6.3K]

Answer:

The percentage ≅ 48.4%

Step-by-step explanation:

* Lets revise how to find the volume of a container shaped cylinder

- The volume of any container = area of its base × its height

- The base of the cylinder is a circle, area circle = 2 π r,

  where r is the length of its radius

* In container A:

∵ r = 13 feet  , height = 13 feet

∴ Its volume = π (13)² × (13) = 2197π feet³

* In container B:

∵ r = 9 feet  , height = 14 feet

∴ Its volume = π (9)² × (14) = 1134π feet³

* So to fill container B from container A, you will take from

  container A a volume of 1134π feet³

- The volume of water left in container A = 2197π - 1134π = 1063π feet³

* To find the percentage of the water that is full after pumping

  is complete, divide the volume of water left in container A

  by the original volume of the container multiplied by 100

∴ The percentage = (1063π/2197π) × 100 = 48.3841 ≅ 48.4%

7 0
4 years ago
Two cars leave Denver at the same time and travel in opposite directions. One car travels 10 mi/h faster than the other car. The
mestny [16]
Recall your d = rt, distance =  rate * time

let's say we have two cars, A and B, B has a speed rate of "r", so A is the faster one and has a speed rate of " r + 10 "

they both are 300 miles apart after 3hrs, after 3hrs, car has been running for 3hrs, and car B has also been running for 3hrs, so their time is the same

we know their distances added up, is 300miles, so if car B covered say, "d" distance on those 3hrs, car A covered the slack, " 300 - d "

\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{car A}&300-d&r+10&3\\
\textit{car B}&d&r&3
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
300-d=(r+10)3\\
\boxed{d}=3r\\
----------\\
300-\boxed{3r}=3(r+10)
\end{cases}

solve for "r"
8 0
4 years ago
SIMPLY 3x(2x2 - 10x + 1)
AnnyKZ [126]
Simplified: 6x^3- 30x^2+3x

Hope this is helpful. :)

8 0
3 years ago
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