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Zielflug [23.3K]
2 years ago
10

A croissant shop has plain croissants, cherry croissants, chocolate croissants, almond croissants, apple croissants, and broccol

i croissants. How many ways are there to choose 26 croissants with at least one plain croissant, at least two cherry croissants, at least three chocolate croissants, at least one almond croissant, at least two apple croissants, and no more than three broccoli croissants
Mathematics
1 answer:
rjkz [21]2 years ago
5 0

Answer:

27405

Step-by-step explanation:

There are 6 different variants available for each croissant. There are 26 croissants in all out of which 1 is plain. We use combination and permutation technique to identify different ways to choose croissant.

[5 + 26 - 1 ] 26 = 30C26 = 27405.

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Snowcat [4.5K]

Answer:

<h2>3(cos 336 + i sin 336)</h2>

Step-by-step explanation:

Fifth root of 243 = 3,

Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),

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Equating equal parts and using de Moivre's theorem:

r^5 =243  and  cos  5Ф  + i sin  5Ф = cos 240 + i sin 240

r = 3 and  5Ф = 240 +360p so Ф =  48 + 72p

So Ф = 48, 120, 192, 264, 336  for   48 ≤ Ф < 360

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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