1. D. 6x-18
2. D. -3/4n+3/8
3. 4(d+3)
Perpendicular lines have opposite, reciprocal slopes. I'll show you 2 ways to solve.
y - (-4) = (-1/2)(x - 8)
y + 4 = (-1/2)x + 4
y = (-1/2)x
orrrr...
-4 = (-1/2)(8) + b
-4 = -4 + b
b = 0
Well, we don't write "+ 0" because that's just extra work.
y = (-1/2)x
Note if you see an equation like this, know that b (our y-intercept) is 0. If you see something like y = 7, then the slope is 0, but 0 times our x-value would equal 0 and that's also unnecessary.
Please mark brainlest
Two points of intersection are on the number at the coordinates (-1,2) and (4,-8).
Compute the gradient of 
.
Set this equal to the zero vector and solve for the critical points.
The last case has no real solution, so we can ignore it.
Now,
so we have two critical points (0, 0) and (2, 2).
Compute the Hessian matrix (i.e. Jacobian of the gradient).
Check the sign of the determinant of the Hessian at each of the critical points.
which indicates a saddle point at (0, 0);
We also have 
, which together indicate a local minimum at (2, 2).
4-(6x + 5) = 7 - 2(3x + 4)
Distribute: 4 - 6x - 5 = 7 - 6x - 8
Combine like terms (constants): -1 - 6x = -1 - 6x
Add 1 to both sides: -6x = -6x
Divide both sides by -6: x = x
Hope this helps!
