Can someone please help me

A typical red blood cell in human blood has a diameter of approximately 0.0007 cm. Enter this diameter in scientific notation.

jonny [76]

Answer:

7-E -4

Step-by-step explanation:

My school supplyes us with a calculator and lucky for you it does scientific notation

8 0

3 years ago

One more question on this test guys. please answer as fast as possible. If you do,

GaryK [48]

1. The given rectangular equation is $x=2$ .

We substitute $x=r\cos \theta$ .

$r\cos \theta=2$

Divide through by $\cos \theta$

$r=\frac{2}{\cos \theta}$

$r=2}\sec \theta$

$\boxed{x=2\to r=2\sec \theta}$

2. The given rectangular equation is:

$x^2+y^2=36$

This is the same as:

$x^2+y^2=6^2$

We use the relation $r^2=x^2+y^2$

This implies that:

$r^2=6^2$

$\therefore r=6$

$\boxed{x^2+y^2=36\to r=6}$

3. The given rectangular equation is:

$x^2+y^2=2y$

This is the same as:

We use the relation $r^2=x^2+y^2$ and $y=r\sin \theta$

This implies that:

$r^2=2r\sin \theta$

Divide through by r

$r=2\sin \theta$

$\boxed{x^2+y^2=2y\to r=2\sin \theta}$

4. We have $x=\sqrt{3}y$

We substitute $y=r\sin \theta$ and $x=r\cos \theta$

$r\cos \theta=r\sin \theta\sqrt{3}$

This implies that;

$\tan \theta=\frac{\sqrt{3}}{3}$

$\theta=\frac{\pi}{6}$

$\boxed{x=\sqrt{3}y\to \theta=\frac{\pi}{6}}$

5. We have $x=y$

We substitute $y=r\sin \theta$ and $x=r\cos \theta$

$r\cos \theta=r\sin \theta$

This implies that;

$\tan \theta=1$

$\theta=\frac{\pi}{4}$

$\boxed{x=y\to \theta=\frac{\pi}{4}}$

6 0

3 years ago

Plz help I’m getting timed

Fed [463]

id say its a rhombus. all the other shapes can have right angles

6 0

3 years ago

Read 2 more answers

Ve the equation. 3c + 1 = c +1

yKpoI14uk [10]

Subtract C in both sides:
2c + 1 = 1

Subtract 1 on both sides
2c = 0

The solution is:
x = 0

Hope this helped

4 0

3 years ago

Select the two figures that are similar to the 5 by 10 figure that is shown.

Lapatulllka [165]

Answer:

Figure (i) and (iv)

Step-by-step explanation:

Given:

Optional figure is given in attached file.

We need to find two figures that are similar to the 5 by 10 figure.

All the given figure are $m\times n$ form.

Where m represent the number of rows and n represent the number of columns.

Solution:

Observe that in the given figure 5 by 10, the number of rows is 5 and number of columns is 10, that is, the number of columns is double of that the number of rows.

So we need to find two such figures whose number of columns is double of the number of rows.

From the given figures, figure (i) the number of rows is 2 and number of columns is 4, which is double of number of rows. so it is similar to 5 by 10 figure.

Similarly in figure (iv), the number of rows is 4 and number of columns is 8. so the number of columns is double the number of rows, so it is similar to the figure 5 by 10.

Therefore, the two figures that are similar to 5 by 10 figure are given in attached file such as (i) and (iv).

6 0

3 years ago