Given:
The system Mx+Ny=P has a solution (1,3) where Rx+Sy=T; <span>M, N, P, R,S and T are non-zero real numbers.
Solve for M, N, R, P, S, T:
M +3N = P
R + 3S = T
The given choices should simplify to the equations above.
A) Mx +Ny = P
7Rx + 7Sy = 7T
7(Rx + Sy) = 7T
Rx + Sy = T
remarks: CORRECT
B) (M+R)x + (N+S)y = P + T
Rx + Sy = T
Mx + Rx + Ny + Sy = P + T
Mx + Ny + T = P + T
Mx + Ny = P
remarks: CORRECT
C) Mx + Ny = P
(2M - R)x + (2N - S)y = P - 2T
2Mx - Rx + 2Ny - Sy = P - 2T
2(Mx + Ny) - (Rx + Sy) = P - 2T
2P - (Rx + Sy) = P - 2T
remarks: INCORRECT
</span>
F(x) = (x - 3)(x - 7)
expanding the brackets gives:
f(x) = x^2 - 10x + 21
its 7y bcs y + 7 is addition,y / 7 is division and y - 7 is subtraction
Hey!
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Answer:
a) -20
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Solution and Explanation:
|-20| = 20
|0| = 0
|10| = 10
|-10| - 10
As we can see, the first option has the greatest absolute value.
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Hope This Helped! Good Luck!
