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Lesechka [4]
3 years ago
14

What’s the answer to this question? x² = 12 16 48

Mathematics
1 answer:
Setler79 [48]3 years ago
8 0
I said it’s probably 16 !!
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Brandon was playing a video game where he scores three points for each treasure he finds. If he found 32 treasures on the first
ratelena [41]

Answer:

300 points

Step-by-step explanation:

32 treasures means he has 32*3 points which is 96 points.

68 treasures means he has 68*3 points which is 204 points.

96+204 is 300

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2 years ago
Suppose the diameter of a circle is in inc what is the radius
Vikentia [17]

Answer:

pi4

Step-by-step explanation:

Formula is piD, diamter is 4, so pi4 which equals 12.56

BRAINYLIST

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3 years ago
What is the slope of the line y = -1/4x?
Mrrafil [7]

The slope is -1/4. Hope this helps! Please mark brainliest! Thank you v much! :)

8 0
4 years ago
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The domain for the following function is ____ ?
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Answer:

All real numbers except x cannot equal 10.

Step-by-step explanation: the denominator can not equal to zero that is undefined.

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3 years ago
A candle in the shape of a circular cone has a base of radius r and a height of h that is the same length as the radius. which e
ladessa [460]

Answer:

\frac{r(1-\sqrt{2})}{-3}

Step-by-step explanation:

Volume of cone = \frac{1}{3} \pi r^{2} h

Since we are given that a circular cone has a base of radius r and a height of h that is the same length as the radius

                          = \frac{1}{3} \pi r^{2} \times r

                          = \frac{1}{3} \pi r^{3}

Surface area of cone including 1 base = \pi r^{2} +\pi\times r \times \sqrt{r^2+h^2}

Since r = h

So, area = \pi r^{2} +\pi\times r \times \sqrt{r^2+r^2}

              = \pi r^{2} +\pi\times r \times \sqrt{2r^2}

              = \pi r^{2} +\pi\times r^2 \times \sqrt{2}

Ratio of volume of cone to its surface area including base :

\frac{\frac{1}{3} \pi r^{3}}{\pi r^{2} +\pi\times r^2 \times \sqrt{2}}

\frac{\frac{1}{3}r}{1+\sqrt{2}}

\frac{r}{3(1+\sqrt{2})}

Rationalizing

\frac{r}{3(1+\sqrt{2})} \times \frac{1-\sqrt{2}}{1-\sqrt{2}}

\frac{r(1-\sqrt{2})}{-3}

Hence the ratio the ratio of the volume of the candle to its surface area(including the base) is \frac{r(1-\sqrt{2})}{-3}

8 0
3 years ago
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