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bekas [8.4K]
4 years ago
15

an object is thrown off a platform that is 15 ft high with an initial velocity of 8.5 ft/is what function models the height h of

the object after t seconds
Mathematics
1 answer:
NemiM [27]4 years ago
4 0

Answer:

Therefore the function that models the height of the object after t seconds is given by "H(t) = 15 + 8.5*t + 16.09*t²".

Step-by-step explanation:

Since the object has a initial velocity and it's being accelerated by gravity, than it's height is defined by:

H(t) = H(0) + V(0)*t + 0.5*g*t²

Applying the data from the problem, we have:

H(t) = 15 + 8.5*t + 0.5*32.17405*t²

H(t) = 15 + 8.5*t + 16.09*t²

Therefore the function that models the height of the object after t seconds is given by "H(t) = 15 + 8.5*t + 16.09*t²".

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Harrizon [31]

Answer:

119\frac{4}{7}

Step-by-step explanation:

10 + 12 + 15 + 24 + 12 + 10 + 35 = 118

\frac{1}{7} + \frac{2}{7}  + \frac{3}{14} + \frac{1}{14}  +\frac{2}{7} + \frac{1}{7} + \frac{3}{7} = \frac{11}{7}

118 + 1 \frac{4}{7}

119 + \frac{4}{7}

119\frac{4}{7}

3 0
4 years ago
Read 2 more answers
Uma secretária possui 6 camisas, 4 saias, e 3 pares de sapatos. Qual o número de maneiras distintas com que a secretária poderá
juin [17]

Answer:

72 maneiras

Step-by-step explanation:

O que acontecerá aqui é que um de cada tipo de roupa será selecionado.

Das 6 camisas, 1 será selecionada O número de maneiras pelas quais podemos fazer isso é 6C1 = 6

Das saias também, ela estará selecionando uma O número de maneiras que isso pode ser feito é 4C1 = 4

O terceiro é selecionar um par de sapatos de 3 e isso seria 3C1 = 3

assim o número de maneiras pelas quais ela pode fazer as seleções é 6 * 4 * 3 = 72 maneiras

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3 years ago
Rhianna works at the gym
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Answer:

they will work together at 12 Days

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3 years ago
A group of transfer bound students wondered if they will spend the same mean amount on texts and supplies each year at their fou
Jet001 [13]

Answer:

We accept H₀. We don´t have enough evidence to support the difference between the two means

Step-by-step explanation:

Group 1 : Comunity College

Sample:

size  :   n₁  = 54

Sample mean    x₁  = 947

Sample standard deviation     s₁ = 254

Group 2 : Local University

Sample

size  :  n₂  =  66

Sample mean :  x₂  = 1011

Sample standard deviation    s₂  =  87

Significance level  α  = 0,05      α  =  5 %      CI = 95 %

Both samples are with n> 30 so we can use z table for the test

from z-table we find  z(c)  =  1,96

The problem statement establishes to run a hypothesis test to determine if the means are statistically the same  ( or different) then we use two-tail-test

Hypothesis Test

Null Hypothesis                        H₀             x₁   -  x₂  = 0 or    x₁  = x₂

Alternative hypothesis             Hₐ             x₁  -  x₂  ≠  0  or    x₁ ≠ x₂

To calculate

z(s)  =  (  x₁   -  x₂  ) / √ s₁²/n₁  + s₂²/n₂ )

z(s)  =  947  -  1011 / √  (254)²/54   +  (87)² / 66

z(s) = -  64  /√ 1194,74  +  114,68

z(s) =  - 64  / 36,185

z(s) =  - 1,77

Comparing modules of  |z(c)|  and |z(s)|

z(s) < z(c)

Then z(s) is in the acceptance region we accept H₀ . There is not enough evidence to support differences in the means of the two groups

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