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dimulka [17.4K]
3 years ago
12

Determine the period.

Mathematics
1 answer:
dimulka [17.4K]3 years ago
8 0

Answer:

4

Step-by-step explanation:

The period is the length of one cycle.

By cycle, I mean the smallest piece that can be traced and copied over and over to form the whole graph. If you notice the graph starts at x=0 and the curve makes a complete cycle by x=4. The cycle starts over again at x=4 and ends at x=8. I hope you are seeing the graph looks exactly the same from x=0 to x=4 as x=4 to x=8.

The length of one cycle of this graph is 4.

Please let me know if you have further questions about this question.

Thank you.

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JulsSmile [24]
<span> Let x be the smaller number.
Then 3x is the larger number.
We also know that the smaller added to the larger is 52, or:
x + 3x = 52
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Carl’s monthly income is $4,000. The circle graph below shows Carl’s monthly budget.
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Step-by-step explanation:

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3 years ago
Find QR. <br> A).12<br> B).-8<br> C).9<br> D).6
mihalych1998 [28]

Answer:

D. 6

Step-by-step explanation:

Let's first find x :-

\sf 3 + 2x + 22 = x + 17

  • \sf 2x + 25 = x + 17
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  • \sf x =  - 8

Now that we found x, let's find QR :-

QR = 2x + 22

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Therefore, QR = 6 !!!

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The probability of passing the math class of Professor Goodrum is 59%, the probability of passing Professor Cruise's physics
liq [111]

Answer:

  51%

Step-by-step explanation:

Given P(passing math) = 59%, P(passing physics) = 26%, and P(passing both) = 17%, you want to find the probability of passing only one of the courses.

<h3>Probability relations</h3>

We can record the given probabilities in a 2-way table (values shown in blue). The table is completed by making sure the totals add up (values shown in black).

The probability of passing one course and failing the other is the sum of the probabilities with a yellow background:

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The probability of passing one or the other is 51%.

__

<em>Additional comment</em>

We can also get there using the relation ...

  P(A+B) = P(A) +P(B) -P(AB)

The union of A and B also includes their overlap:

  P(A+B) = P(AB') +P(A'B) +P(AB)

In other words, the probability of interest is ...

  P(AB') +P(A'B) = P(A) +P(B) -2×P(AB) = 59% +26% -2(17%)

  P(AB') +P(A'B) = 51%

6 0
1 year ago
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