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Vesnalui [34]
3 years ago
8

Evaluate 5c +cd when c = 1/5 and d= 15

Mathematics
2 answers:
Kitty [74]3 years ago
8 0
4 is the answer because you multiply
nirvana33 [79]3 years ago
4 0
The answer would be 4, here are the steps. :)

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What is the solution for the equation startfraction 5 over 3 b cubed minus 2 b squared minus 5 endfraction = startfraction 2 ove
kaheart [24]

An equation is formed of two equal expressions. The solution of the equation is 4.

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.


The solution of the equation can be written as,

\dfrac{5}{3b^3-2b^2-5} = \dfrac{2}{b^3-2}\\\\5(b^3-2) = 2(3b^3-2b^2-5)\\\\5b^3-10=6b^3-4b^2-10\\\\5b^3-10-6b^3+4b^2+10=0\\\\-b^3+4b^2=0\\\\b^2(-b+4)=0\\\\-b+4=0\\\\-b=-4\\\\b=4

Thus, the solution of the equation is 4.

Learn more about Equation:

brainly.com/question/2263981

6 0
2 years ago
Read 2 more answers
The math class is 45 minutes long. If announcements are 5 minutes long, the warm up is 7 minutes long and the notes take 11 minu
atroni [7]

Answer:

22?

Step-by-step explanation:

7 0
4 years ago
In circle E with m DEF 36 and DE = 3 units find area of
deff fn [24]

Answer:

A ≈ 2.83 units²

Step-by-step explanation:

The area (A) of the sector is calculated as

A = area of circle × fraction of circle

   = πr² × \frac{36}{360}

   = π × 3² × \frac{1}{10}

    = \frac{9\pi }{10}

   ≈ 2.83 units² ( to the nearest hundredth )

4 0
3 years ago
PLZ HELP WITH THESE QUESTIONS!!!!!!!!!!
Oduvanchick [21]
Which one of these ?
4 0
4 years ago
Find the intercepts and asymptotes, use limits to describe the behavior at the vertical asymptotes. (37 and 39)
n200080 [17]
39)
Its always best to factorise where you can, in most questions it tends to be a necessary step and even if its not, it usually makes things easier;
In this case, you can factorise the denominator:
h(x) = \frac{x \ - \ 1}{ x^{2} \ - \ x \ - \ 12} \\\\ = \frac{x \ - \ 1}{(x \ - \ 4)(x \ + \ 3)}

To get y-intercept/s, set x = 0 and solve:
h(0) = \frac{(0) \ - \ 1}{((0) \ - \ 4)((0) \ + \ 3)} \\\\ =  \frac{-1}{-12} \\\\ =  \frac{1}{12}
y-intercept: (0, 1/12)

To get x-intercept/s, set y = 0 and solve:
\frac{x \ - \ 1}{(x \ - \ 4)(x \ + \ 3)} = 0 \\\\ x \ - \ 1 = 0 \\\\ x = 1
x-intercept: (1, 0)

To find the asymptotes, it is necessary for us to have factorised the denominator so its a good thing that I did so at the beginning;

To get the vertical asymptote/s, set the denominator equal to 0, then just rearrange to get x:
(x \ - \ 4)(x \ + \ 3) = 0 \\ x \ - \ 4 = 0 \\ x = 4 \\ and \\ x \ + \ 3 = 0 \\ x = -3
vertical asymptotes: x = 4  and  x = -3

There are no horizontal asymptotes.
8 0
4 years ago
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