Hi!
The equation of a circle is (x – h)² + (y – k)² = r², with (h, k) being the center, r being the radius, and x + y being left as just x and y.
If the smallest circle has a radius of 3 units, then the next one is 7 units (4 units greater), and then the second largest 11 units, and then the largest 15. That means, for r in our equation, we're going to put in 15.
So we get:
(x – h)² + (y – k)² = 15², or
(x – h)² + (y – k)² = 225
The center of our circle is at (-4, 3). That means h = -4 and k = 3 in our equation. So let's substitute that in.
(x – (-4))² + (y – 3)² = 225
(x + 4)² + (y - 3)² = 225 is our final equation.
Hope this helped!
Answer:
Y=s^2/36 and y=5.7;14.3 ft
Step-by-step explanation:
The question was not typed correctly. Here, a better version:
<em>The aspect ratio is used when calculating the aerodynamic efficiency of the wing of a plane for a standard wing area, the function A(s)=s^2/36 can be used to find the aspect ratio depending on the wingspan in feet. If one glider has an aspect ratio of 5.7, which system of equations and solution can be used to represent the wingspan of the glider? Round solution to the nearest tenth if necessary. </em>
<em>
</em>
<em>Y=s^2/36 and y=5.7;14.3 ft
</em>
<em>Y=5.7s^2 and y=36; s=2.5ft
</em>
<em>Y=36s^2 and y=0; s=0.4 ft
</em>
<em>Y=s^2/36 +5.7 and y=0; s=5.5 ft</em>
In the function A(s)=s^2/36 A(s) represents the aspect ratio and s the wingspan. If one glider has an aspect ratio of 5.7, then A(s) = 5.7. We want to know the wingspan of the glider. Replacing A(s) by Y we get the following system of equation:
Y=s^2/36
with y = 5.7
5.7 = s^2/36
5.7*36 = s^2
√205.2 = s
14.3 ft
Its the 3rd from the left good luck
it takes 2 bags for each turkey for a week
4 weak are there in a month
so for one turkey=4*2
=8
so for one turkey its 8 means
2 turkey=8+8
=16
therefore it takes 16 bags for two turkey in a month
last one is the solution u should choose
