Answer:
Step-by-step explanation:
1) ABCD is a trapezium. AB ║ CD
∠ADC + ∠DAB = 180° { Co interior angles}
110° + ∠DAB = 180
∠DAB = 180 -110
∠DAB = 70°
2) Sum of all angles of trapezium = 360°
∠A + ∠B + ∠DCB + ∠D = 360
70° + 50° + ∠DCB + 110° = 360
230 + ∠DCB = 360
∠DCB = 360 - 230
∠DCB = 130°
3) For finding the height, use Pythagorean theorem
height² + base² = hypotenuse²
height² + 6² = 10²
height² + 36 =100
height² = 100 - 36
height² = 64
height = √64
height = 8 m
4) a = AB = x m
b = 9 m
h = height = 8 m
Area of trapezium = 120 m²
= 120
x + 9 = 120/4
x + 9 = 30
x = 30 - 9
x = 21 m
AB = 21m
1. You will have to find the height first which could be done by using pythagoras theorem
split the 12 by half giving 6
a^2 = b^2 + c^2
13^2 = 6^2+c^2
169 = 36+c^2
c^2=169-36
c^2=133
c=sqrt133
c= 11.53
area of triangle
1/2 x b x h
1/2 x 6 x 11.53
34.59
34.5(3 sf)
Answer:
C
Step-by-step explanation:
Quadratic formula is used only to solve the quadratic equations .
Means the equation of the form
In this the x^2 part is must because that only makes the equation a quadratic.
Looking at the four options given to you , only the option C has the missing x^2 term, which makes it a linear equation and hence the quadratic formula cannot be applied there .
So the right option for your question with the quadratic formula is
option
C
Answer:
i.e. relation between speed-distance-time is one such situation that can be modeled using graph
Step-by-step explanation:
There are many real world examples that can be modeled using graph. Graphs are represented on co-ordinate planes, so any real world example that can be represented by use of linear equation can be represented onto a graph.
One such example, is speed-distance-time relation. Uniform speed can be represented on a graph as shown in figure.
So, the equation for speed is represented by equation as follows:
So, if we take distance on y axis and time on x axis with points as (distance,time)
(0,0) ==> 
(1,2) ==> 
(2,2) ==> 
the following points 0,0.5,1 will be plotted on graph. Similarly, more values can be plotted by assuming values for distance and time.
Although there is no picture, I will assume this is a triangle we are talking about since the terms base and height are being used. If that is the case, the height is roughly 38.72in.
To find this, we will use the area of a triangle formula.
1/2bh = a ---> plug in known values.
1/2(12.6)(h) = 244 ---> multiply to simplify
6.3(h) = 244 ----> divide both sides by 6.3
h = 38.73
