Answer:
If sin 115 degrees≈ 0.91 and cos 115 degrees = -0.42, then sin -115 = -0.91 and cos -115 degrees = 0.42
Step-by-step explanation:
Answer:
Let's simplify step-by-step.
3x2+9x+6−(8x2+3x−10)+(2x+4)(3x−7)
Distribute:
=3x2+9x+6+−8x2+−3x+10+(2x)(3x)+(2x)(−7)+(4)(3x)+(4)(−7)
=3x2+9x+6+−8x2+−3x+10+6x2+−14x+12x+−28
Combine Like Terms:
=3x2+9x+6+−8x2+−3x+10+6x2+−14x+12x+−28
=(3x2+−8x2+6x2)+(9x+−3x+−14x+12x)+(6+10+−28)
=x2+4x+−12
Answer:
=x2+4x−12
![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for
is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of
is always positive for
. That means at
there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function
is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
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