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soldi70 [24.7K]
3 years ago
15

Frannie's age is 17, which is 7 more than twice Brynn's age. ​Write an equation that could be used to find Brynn's age, b.

Mathematics
1 answer:
Elanso [62]3 years ago
7 0

Answer:17 x 7= y x 2

Step-by-step explanation:

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Henry is fishing from a small boat. His fishing hook is in the water 8 meters directly below his boat. A fish is swimming at the
Angelina_Jolie [31]

Answer: 17

Step-by-step explanation:

8 0
2 years ago
Aidan looked at how many people ride the morning
SashulF [63]

Answer:

Average number of people ride ferry boat = 62 or 63 people

Step-by-step explanation:

Given:

Number of people ride ferry boat

58 59 60 61 62 63 64 65 66 67

Find:

Average number of people ride ferry boat

Computation:

Average mean = Sum of all observation / Number of observation

Average number of people ride ferry boat = [58 + 59 + 60 + 61 + 62 + 63 + 64 + 65 + 66 + 67] / 10

Average number of people ride ferry boat = [625] / 10

Average number of people ride ferry boat = 62.5

Average number of people ride ferry boat = 62 or 63 people

5 0
3 years ago
Use the commutative and associative properties of multiplication to write an expression equivalent to (4⋅5)⋅3.
Darina [25.2K]
Commutaive property says
ab=ba or expanded to say
abc=cba

associative peropty =
a(bc)=(ab)c

so using that
first mix them up knowing that we can move the parenthaseese
all possible equivelnt ones are
4*(5*3)
(3*5)*4
3*(5*4)
(3*4)*5
3*(4*5)
 
4 0
3 years ago
Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

8 0
3 years ago
Guys please help me. I am stuck read the directions to see what to do ps: thanks
AleksandrR [38]
5; 6; 4; 14; 6
12; 2; 2; 68; 21
4; 10; 6; 32; 34
3;4;66;2;5
36;18;3 1/2;12/5;2
that's all i believe
3 0
3 years ago
Read 2 more answers
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