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3 years ago

Point T is on SU ST=20 and TU=8 what is SU?

Mathematics

1 answer:

Umnica [9.8K]3 years ago

4 0

SU would be 28 units because T is between S and U so you have to add ST and TU to get the length of the entire line

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A triangular lamina has vertices (0, 0), (0, 1) and (c, 0) for some positive constant c. Assuming constant mass density, show th

a_sh-v [17]

The equation of the line through (0, 1) and (c, 0) is

y - 0 = (0 - 1)/(c - 0) (x - c) ==> y = 1 - x/c

Let L denote the given lamina,

L = {(x, y) : 0 ≤ x ≤ c and 0 ≤ y ≤ 1 - x/c}

Then the center of mass of L is the point $(\bar x,\bar y)$ with coordinates given by

$\bar x = \dfrac{M_x}m \text{ and } \bar y = \dfrac{M_y}m$

where $M_x$ is the first moment of L about the x-axis, $M_y$ is the first moment about the y-axis, and m is the mass of L. We only care about the y-coordinate, of course.

Let ρ be the mass density of L. Then L has a mass of

$\displaystyle m = \iint_L \rho \,\mathrm dA = \rho\int_0^c\int_0^{1-\frac xc}\mathrm dy\,\mathrm dx = \frac{\rho c}2$

Now we compute the first moment about the y-axis:

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Then

$\bar y = \dfrac{M_y}m = \dfrac{\dfrac{\rho c^2}6}{\dfrac{\rho c}2} = \dfrac c3$

but this clearly isn't independent of c ...

Maybe the x-coordinate was intended? Because we would have had

$\displaystyle M_x = \iint_L y\rho\,\mathrm dA = \rho \int_0^c\int_0^{1-\frac xc}y\,\mathrm dy\,\mathrm dx = \frac{\rho c}6$

and we get

$\bar x = \dfrac{M_x}m = \dfrac{\dfrac{\rho c}6}{\dfrac{\rho c}2} = \dfrac13$

8 0

3 years ago

Pls answer correctly

muminat

The rule for the area of a polygon is as follows:

Area of a Polygon = Apothem x Perimeter ÷ 2

So, add all the of the outside measurements together to find the Perimeter but I don't know where the Apothem in the polygons are.

I hope this gives you some sort of a lead. :)

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valkas [14]

Answer:

13 uvugugugugycycycycycycy

Step-by-step explanation:

cycle yvy

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