What is the rest of the question
Answer:
- 278.4°F
Step-by-step explanation:
Temperature of Object ( T ) = 1200° F
Temperature of surrounding ( M ) = 80°F
Time ( t ) = 1 hour
dT / dt ∝ ( M - T )
dT /dt ∝ | ( 80 - 1200 ) |
dT / dt = k ( 1120 )
(1200 - 830 ) / 1 = k ( 1120 )
hence k = ( 1200 - 830 ) / 1120
= 370 / 1120 = 0.33
<u>what is the object's temperature (x )after 4 hours </u>
( 1200 - x ) / 4 = 0.33 ( 1120 )
( 1200 - x ) / 4 = 369.6
hence x = 1200 - ( 4 * 369.6 )
= - 278.4 ° F
2/5 * (n - 1) < 3/5 * (n + 1)
2/5 * n - 2/5 < 3/5 * n + 3/5
- 2/5 - 3/5 < 3/5 * n - 2/5 * n
- 5/5 < 1/5 * n
- 1 < 1/5 * n /*5
- 5 < n
n > - 5
n = x
The correct result would be B) <span>x > - 5.</span>
To find the product of (4x-5y)^2,
we can rewrite the problem as:
(4x-5y)(4x-5y) (two times because it is squared)
Now, time to use that old method we learned in middle school:
FOIL. (Firsts, Outers, Inners, and Lasts)
FOIL can help us greatly in this scenario.
Let's start by multiplying the 'Firsts' together:
4x * 4x = <em>16x^2</em>
Now, lets to the 'Outers':
4x * -5y = <em>-20xy</em>
Next, we can multiply the 'Inners':
-5y * 4x = <em>-20xy</em>
Finally, let's do the 'Lasts':
-5y * -5y = <em>25y</em>^2
Now, we can take the products of these equations from FOIL and combine like terms. We have: 16x^2, -20xy, -20xy, and 25y^2.
-20xy and -20xy make -40xy.
The final equation (product of (4x-5y)^2) is:
16x^2 - 40xy + 25y^2
Hope I helped! If any of my math is wrong, please report and let me know!
Have a good one.
5C2 * (2x)^3 * y^2
5 * 4 / 2 * 8 * x ^ 3 * y ^ 2
20 / 2 * 8 * x ^ 3 * y ^ 2
80 * x^3 y^2
Answer = 80