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aleksandrvk [35]
3 years ago
6

What the radius and diameter

Mathematics
2 answers:
Natasha2012 [34]3 years ago
8 0
On is 26 the second one is 45 cuz 3x3 = 9 so that be 35
vekshin13 years ago
7 0

Answer: 1. The Diameter is 25 and The Radius is 12.5

2. The Radius is 2 and The Diameter is 4

Step-by-step explanation:

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(HELP ASAP) Kite EFGH is inscribed in a rectangle where F and H are midpoints of parallel sides.
Reika [66]
Let's say that FH and EG intersection is O,
So we have the following:
OF = 2
OH = 5

Just because F and H are midpoints it means that EO = OG = x
And as it's given the area S=35

On the other hand
S = OF*OG/2 + OG*OH/2 + OH*OE/2 + OE*OF/2 = 2*x/2 + x*5/2 + 5*x/2 + x*2/2 = 2*x + 5*x = 7*x = 35

7x = 35 so x = 35/7 = 5

Answer: 5 units

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A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2
Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.                  

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?    

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is \frac{1}{20000}

Probability of getting second prize is \frac{2}{20000}

Probability of getting third prize is \frac{20}{20000}

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is \frac{19977}{20000}

The expected value is

E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25

E=\frac{1000+600+200-4994.25}{20000}

E=\frac{-3194.25}{20000}

E=-0.159

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

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