Answer:
2196 fish
Step-by-step explanation:
Weight of fish that the killer whale might eat in a month (30 days) = 14,000 lb
Weight of the fish that killer whale might eat in a day =
lb.
Average weight of the fish that killer whale eats = 3.4 oz
Since,
1 pound(lb) = 16 ounces(oz)
So,
Weight of the fish that killer whale might eat in a day in ounces(oz) =
oz
Since, a certain fish weighs 3.4 oz, in order to find the number of fish that killer whale must eat, we must divide the total weight in ounces by 3.4 ounces.
So, the number of fish that killer whale would eat =
fish
Thus, the killer whale needs to eat 2196 fish.
One factor will be zero, hence y will be zero, when x=-3.
The other factor will be zero, hence y will be zero, when x=-5.
The zeros of the function are x ∈ {-5, -3}.
_____
This solution makes use of the "zero product rule," which states a product is zero if and only if one or more factors is zero.
Hey! Your answer would be 0.0875L
21g=84
g=84/21
g=4
The answer is B
Answer: 3/8
There are only three numbers in there that 2 and 3 can go into evenly.
The probability that you will randomly select one of those numbers is 3/8.
-Brainly Answerer