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riadik2000 [5.3K]
3 years ago
15

Convert 3.5 multiplied by 10 and 4 square root

Mathematics
1 answer:
AURORKA [14]3 years ago
7 0
The answer is the first one, 35000.
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Suppose a random variable, x, arises from a binomial experiment. If n = 25, and p = 0.85, find the variance. Round answer to 4 d
Tamiku [17]

Answer:

<u><em>a) P(X=1) = 0.302526</em></u>

<u><em>b) P(X=5) = 0.010206</em></u>

<u><em>c) P(X=3) = 0.18522</em></u>

<u><em>d) P(X≤3) = 0.92953</em></u>

<u><em>e) P(X≥5) = 0.010935</em></u>

<u><em>f) P(X≤4) = 0.989065</em></u>

<u><em></em></u>

<u><em></em></u>

<u><em>If helpful, please mark as brainliest! =)</em></u>

8 0
3 years ago
HELP PLEASE
GREYUIT [131]
The Answer is (D. No solution)
6 0
3 years ago
Help , which segment is congruent to al
svetlana [45]

CI is congruent to AI

Step-by-step explanation:

Congruent means  they are identical, CI and AI are identical

5 0
3 years ago
Who do I do this problem
Leviafan [203]
You subtract 16 from each side of the equation.
Then it will say exactly what number 'n' is.
_______________________________________

The equation is                    n + 16 = 9

On the left side, you subtract 16 from (n + 16) and you have 'n'.

On the right side, you subtract 16 from 9 and you have  -7 .

Now the equation says          n      =  -7
3 0
3 years ago
A coin is tossed 4 times. Let E1 be the event "the first toss shows heads" and E2 the event "the second toss shows heads" and so
Elden [556K]

Answer:

The events are independent.

The probability of showing heads on both toss is equal to 1/2

Step-by-step explanation:

The sample space for this experiment consists of 2⁴= 16 sample points, as each toss can result in two outcomes we assume that the events are equally likely.

Two events are independent in the sample space if the probability of one event occurs, is not affected by whether the other event has or has not occurred.

In general the k events are defined to be mutually independent if and only if the probability of the intersection of  any 2,3,--------, k  equals the product of their respective probabilities.

P (A∩B) = P(A). P(B)

P (A∩B)   = 1/2. 1/2= 1/4

                                                                  Head          Tail

 P(E1)= 1/2  ----------          Coin 1               H,H              T,H

                                                                1/4                  1/4

  P(E2)= 1/2  ---------------  Coin 2             H, H               H,T

                                                                      1/4           1/4

So the events are independent.

The probability of showing heads on both toss is equal to 1/2

The sample space for this experiment consists of 2⁴= 16 sample points, out of which eight will have heads on both toss.

Or in other words ( 1/4* 1/4) = 2/4 = 1/2

4 0
3 years ago
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