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2 years ago

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Mathematics

2 answers:

xxTIMURxx [149]2 years ago

6 0

Area=

$\pi \times r {}^{2}$

1)To find radius diameter/2

21.5÷2=10.75

$10.75 {}^{2} \times \pi = 362.87$

area =362.87cm

$\pi \times 13.2 {}^{2} = 547.39$

area=547.39cm

Tanya [424]2 years ago

5 0

Area = pie × ( 21.5 / 2 )^2

Area = pie × ( 10.75 )^2

Area = pie × 115.5625

Area = 3.14 × 115.5625

Area = 362.86625 cm^2

___________________________

Area = pie × ( 13.2 )^2

Area = pie × 174.24

Area = 3.14 × 174.24

Area = 547.1136 ft^2

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HELPPPPPPPPPPPPPPPPPPPP

SVEN [57.7K]

If x + y = 6, then solve for y to get: y = 6 - x.

Now replace y with 6 - x in both equations.

(5x)/3 + 6 - x = c

2(6 - x) = c - 4x

The upper equation is solved for c.
Now we solve the lower equation for c.

c = 2(6 - x) + 4x

c = 12 - 2x + 4x

c = 2x + 12

Since we have two equations solved for c, we substitute to get

(5x)/3 + 6 - x = 2x + 12

This is an equation in only x, so we can solve for x.

(5x)/3 - 3x = 6

5x - 9x = 18

-4x = 18

x = -9/2

Now we solve for y.

x + y = 6

-9/2 + y = 6

y = 9/2 + 12/2

y = 21/2

Now we solve for c.

c = (5x)/3 + y

c = (5 * (-9/2))/3 + 21/2

c = -45/6 + 21/2

c = -15/2 + 21/2

c = 6/2

c = 3

Answer: c = 3

7 0

3 years ago

A line goes through the points (4, 5) and (2, -6). Write the equation of the line in slope-intercept form.

myrzilka [38]

3/4 & 1/-3 would be the answer

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2 years ago

<img src="https://tex.z-dn.net/?f=%24a%2Ba%20r%2Ba%20r%5E%7B2%7D%2B%5Cldots%20%5Cinfty%3D15%24%24a%5E%7B2%7D%2B%28a%20r%29%5E%7B

riadik2000 [5.3K]

Let

$S_n = \displaystyle \sum_{k=0}^n r^k = 1 + r + r^2 + \cdots + r^n$

where we assume |r| < 1. Multiplying on both sides by r gives

$r S_n = \displaystyle \sum_{k=0}^n r^{k+1} = r + r^2 + r^3 + \cdots + r^{n+1}$

and subtracting this from $S_n$ gives

$(1 - r) S_n = 1 - r^{n+1} \implies S_n = \dfrac{1 - r^{n+1}}{1 - r}$

As n → ∞, the exponential term will converge to 0, and the partial sums $S_n$ will converge to

$\displaystyle \lim_{n\to\infty} S_n = \dfrac1{1-r}$

Now, we're given

$a + ar + ar^2 + \cdots = 15 \implies 1 + r + r^2 + \cdots = \dfrac{15}a$

$a^2 + a^2r^2 + a^2r^4 + \cdots = 150 \implies 1 + r^2 + r^4 + \cdots = \dfrac{150}{a^2}$

We must have |r| < 1 since both sums converge, so

$\dfrac{15}a = \dfrac1{1-r}$

$\dfrac{150}{a^2} = \dfrac1{1-r^2}$

Solving for r by substitution, we have

$\dfrac{15}a = \dfrac1{1-r} \implies a = 15(1-r)$

$\dfrac{150}{225(1-r)^2} = \dfrac1{1-r^2}$

Recalling the difference of squares identity, we have

$\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}$

We've already confirmed r ≠ 1, so we can simplify this to

$\dfrac2{3(1-r)} = \dfrac1{1+r} \implies \dfrac{1-r}{1+r} = \dfrac23 \implies r = \dfrac15$

It follows that

$\dfrac a{1-r} = \dfrac a{1-\frac15} = 15 \implies a = 12$

and so the sum we want is

$ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}$

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?

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2 years ago

Hans wanted to find the length of the hypotenuse of the triangle. Which statement correctly identifies his error?

KonstantinChe [14]

Choice 1. He did not square 40, he just multiplied by 2.

Step-by-step explanation:

Step 1:

According to the Pythagorean theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

The hypotenuse measures c cm while the other sides are 40 cm and 9 cm each.

Step 2:

According to the Pythagorean theorem,

$9^{2} +40^{2} = c^{2}.$

$81 + 1600 = c^{2} .$

$1681 = c^{2} .$

$\sqrt{1681} = c.$

This is the correct solution to the given problem. Hans did not square 40, he just multiplied by 2. Which is the first option.

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3 years ago

Connor wants to attend the town carnival. The price of admission to the

Vesna [10]

Answer:

14 rides

Step-by-step explanation:

16 = 0.79x + 4.5

11.5 = 0.79x

x = 14.55 or 14

rounding down because it can't go over $16.

0.79(14) + 4.5 = $15.56

7 0

2 years ago