What is the slope of the line that passes through the points (8,4) and (20,-4)?

A manufacturing company produces 3 different products A, B, and C. Three types of components, i.e., X, Y, and Z, are used in the

Murljashka [212]

Answer:

Step-by-step explanation:

Using the Excel Formula:

Decision Variable Constraint Constraint

A 65 65 100

B 80 80 80

C 90 90 90

14100 300 300

= (150 *B3)+(80*B4) +(65*B5)-(100-B3+80-B4+90-B5)*90

Now, we have:

Suppose A, B, C represent the number of units for production A, B, C which is being manufactured

A B C Unit price

Need of X 2 1 1 $20

Need of Y 2 3 2 $30

Need of Z 2 2 3 $25

Price of

manufac - $200 $240 $220

turing

Now, for manufacturing one unit of A, we require 2 units of X, 2 units of Y, 2 units of Z are required.

Thus, the cost or unit of manufacturing of A is:

$20 (2) + $30(2) + $25(2)

$(40 + 60 + 50)

= $150

Also, the market price of A = $200

So, profit = $200 - $150 = $50/ unit of A

Again;

For manufacturing one unit of B, we require 1 unit of X, 3 units of Y, and 2 units of Z are needed and they are purchased at $20, $30, and 425 each.

So, total cost of manufacturing a unit of B is:

= $20(1) + $30(3) + $25(2)

= $(20 + 90+50)

= $160

And the market price of B = $240

Thus, profit = $240- $160

profit = $80

For manufacturing one unit of C, we have to use 1 unit of X, 2 unit of Y, 3 units of Z are required:

SO, the total cost of manufacturing a unit of C is:

= $20 (1) + $30(2) + $25(3)

= $20 + $60 + $25

= $155

This, the profit = $220 - $155 = $65

However; In manufacturing A units of product A, B unit of product B & C units of product C.

Profit --> 50A + 80B + 65C

This should be provided there is no penalty for under supply of there is under supply penalty for A, B, C is $40

The current demand is:

100 - A

80 - B

90 - C respectively

So, the total penalty

${(100 - A) + (80 - B) +(90 - C) } + \$40$

This should be subtracted from profit.

So, we have to maximize the profit

$Z = 50A + 80B + 65C = {(100 -A) + (80 - B) + (90 - C)};$

Subject to constraints;

we have the total units of X purchased can only be less than or equal to 300 due to supplies capacity

Then;

$2A + B +C \le 300$ due to 2A, B, C units of X are used in manufacturing A, B, C units of products A, B, C respectively.

Next; demand for A, B, C will not exceed 100, 80, 90 units.

Hence;

$A \le 100$

$B \le 80$

$C \le 90$

and $A, B, C \ge 0$ because they are positive quantities

The objective is:

$\mathbf{Z = 50A + 80B + 65 C - (100 - A + 80 - B + 90 - C) * 40}$

A, B, C $\to$ Decision Varaibles;

Constraint are:

$A \le 100 \\ \\ B \le 100 \\ \\ C \le 90 \\ \\2A + B + C \le 300 \\ \\ A,B,C \ge 0$

6 0

3 years ago

Divide.

zzz [600]

The answer is B. 5/6

7 0

3 years ago

Which Is worth more 4.1 billion or 3.914 billion

Xelga [282]

Answer:

the one worth more is 4.1 billion

4 0

3 years ago

Read 2 more answers

If you're ladder is 10 feet long and you place the bottom 6 feet from the wall how far can you reach

-Dominant- [34]

This is like a triangle.
One side, the hypotenuse, is the length of the ladder, 10 feet in this case.
Another side, one of legs, is the distance from the bottom of the ladder to the side of the wall, 6 feet.
The last side is what we need to find, how high up the ladder reaches.

Using the p<span>ythagorean theorem, we can find this third side.
This is written as a^2 + b^2 = c^2.
A and B are the legs, while C is the hypotenuse.

Plugging in known values, we get:
6^2 + b^2 = 10^2

Solve as much as possible:
6^2 = 36
10^2 = 100
36 + b^2 = 100

Now you must isolate b.
Subtract 36 from both sides.
100 - 36 = 64
b^2 = 64

The last step in finding b is doing the inverse of squaring, which is square rooting.
√64 = 8
So b equals 8.

This means that <span>the ladder can reach 8 feet up the wall.</span></span>

6 0

3 years ago

Can anybody help me with this question?

adelina 88 [10]

Answer:

Your answer is c hope this helps

8 0

3 years ago