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3 years ago

Put 2 (n^2 + 8n + 16) in standard form

Mathematics

1 answer:

tino4ka555 [31]3 years ago

6 0

Answer: 2n^2 + 16n + 32

Step-by-step explanation:

Distribute 2 to all the terms inside parentheses.

2 (n^2 + 8n + 16)

2n^2 + 16n + 32

Hope this helped!

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2 years ago

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A shopper is standing on level ground 800 feet from the base of a 250 foot tall department store the shopper looks up and sees a

Aleks04 [339]

Answer:

The elevation to the top of the building from the point on the ground where the shopper is standing is = 17.35°

Step-by-step explanation:

From the ΔABC

AB = height of the building = 250 feet

BC = 800 ft

Angle of elevation = $\theta$

$\tan \theta = \frac{AB}{BC}$

$\tan \theta = \frac{250}{800}$

$\tan \theta$ = 0.3125

$\theta = 17.35$ °

Therefore the elevation to the top of the building from the point on the ground where the shopper is standing is = 17.35°

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3 years ago

Explain how you can tell when a formula represents a length an area or a volume

AlekseyPX

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3 years ago

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The vertex of this parabola is at (2,-1) when the y value is 0 and then x value is 5 what is the coefficient of the squared term

Darina [25.2K]

$\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{2}{ h},\stackrel{-1}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=2\\ k=-1 \end{cases}\implies y=a(x-2)^2-1 \\\\\\ \textit{we also know that } \begin{cases} y=0\\ x=5 \end{cases}\implies 0=a(5-2)^2-1\implies 1=9a \\\\\\ \cfrac{1}{9}=a\qquad therefore\qquad \boxed{y=\cfrac{1}{9}(x-2)^2-1}$

now, let's expand the squared term to get the standard form of the quadratic.

$\bf y=\cfrac{1}{9}(x-2)^2-1\implies y=\cfrac{1}{9}(x^2-4x+4)-1 \\\\\\ y=\cfrac{1}{9}x^2-\cfrac{4}{9}x+\cfrac{4}{9}-1\implies \stackrel{its~coefficient}{y=\stackrel{\downarrow }{\cfrac{1}{9}}x^2-\cfrac{4}{9}x-\cfrac{5}{9}}$