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zepelin [54]
2 years ago
5

NO LINKS!!!!!! Please please help me!!! ASAP

Mathematics
1 answer:
nydimaria [60]2 years ago
5 0

Answer:

PLEASE TAKE YOUR TIME AND THINK THROUGH EVERY PROBLEM. USE THE C.U.B.E.S STRATEGY WHEN NEEDED.

Step-by-step explanation:

You might be interested in
There are several peaches on a plate. Mary took c peaches from the plate, Andrew took the remaining y peaches. How many peaches
Karolina [17]

Answer:

c+y peaches

Step-by-step explanation:

since the questions does not mention any peaches that are left over even after Andrew took the y peaches, the c amount and y amount are all that were on the plate.

8 0
3 years ago
If m∠XWY = 20°, m∠XWZ = 40°, and XY = 16, what is the value of YZ?
Jobisdone [24]
YZ = 16. The triangles are congruent. This would be AAS so YZ = 16 because of CPCTC.
7 0
3 years ago
PLEASE HELP ILL BRAINLIEST YOU ILL GIVE U 50 extra points
Goryan [66]
Don't trust those link my guy
7 0
2 years ago
Plz help I will mark as the brainlist
tensa zangetsu [6.8K]

Answer:

1/25

Step-by-step explanation:

We can see that in this pattern, the denominator and the numerator of the next fraction cancel out; they're the same.

(1/2) x (2/3) x (3/4) = 1/4 (do you see it?)

The only things that do not cancel out are the numerator of the first fraction and the denominator of the last. So, in the end, the answer will be 1/25.

Hope this helps!

3 0
3 years ago
In terms of the trigonometric ratios for ΔABD, what is the length of line segment BD?
erica [24]

In terms of the trigonometric ratios for ΔABD, what is the length of line segment BD?

Answer:

BD = c*sin(A)

BD = c*cos(B)

BD = b*tan(A)

Step-by-step explanation:

∆ABD is a right triangle.

Recall: trigonometric ratios of any right triangle can easily be understood or remembered with the acronym, SOHCAHTOA.

SOH => sin(θ) = opposite/hypotenuse

CAH => Cos(θ) = adjacent/hypotenuse

TOA = tan(θ) = opposite/adjacent

Thus, the length of segment BD, in terms of trigonometric ratios for ∆ABD can be done as follows:

Let BD = x

AB = c

AD = b

=>The sine ratio for the length of line segment BD = x, using SOH.

θ = A

Opposite = DB = x

hypotenuse = AB = c

sin(A) = \frac{x}{c}

Make x the subject of formula.

c*sin(A) = x

BD = x = c*sin(A)

=>The Cosine ratio for the length of line segment BD = x, using CAH

θ = B

Adjacent = DB = x

hypotenuse = AB = c

cos(B) = \frac{x}{c}

Make x the subject of formula.

c*cos(B) = x

BD = x = c*cos(B)

=>The Tangent ratio for the length of line segment BD = x, using TOA

θ = A

Adjacent = DB = x

hypotenuse = AD = b

tan(A) = \frac{x}{b}

Make x the subject of formula.

b*tan(A) = x

BD = x = b*tan(A)

5 0
3 years ago
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