Answer:
t=1.283 seconds and
0.779 seconds
Step by step Explanation:
Given: h=18 ft
The given equation is h=2+33t-16t²
Then if we substitute the value of given h, h=18 ft into the given equation we have,
18=2+33t-16t²
Then if we re- arrange we have
16t²−33t+16=0
We can see that the above quadratic equation is in standard form, with a=16, b=33 and c=16 then we can use quadratic formula in solving it which is
t= −(−33±√[(−33) ²−4×16×16)]/(2×16)
= [33±√[1089−1024]/(32)
= [33±√[65]/(32)
=1.283 or 0.779 seconds
the two real roots , of the quadratic are:
1.283 and
0.779 seconds
t= 1.283 or 0.779 seconds
Hence, the ball is at 18 feet with height 0.779seconds after it has been thrown up and,
and is at 21 feet with height 1.283 seconds after after thrown down
Answer:
i think that the inquality is true but idk the solution..
Step-by-step explanation:
Answer:
She made the error in step 2.
Two negatives equal a positive.
1. 9
2. 8
I hope this helped! #Sobangcha
Answer:
1. -4x + 35 = - 1
2. x = 9 hours
Step-by-step explanation:
Starting at 1:00 pm, temperature changes - 4 degrees Fahrenheit per hour.
At 1:00 pm --> 35 degrees
Our equation will be y = -4x + 35
Substitute -1 in for y:
-4x + 35 = - 1 <--- Answer for the first question
-4x = -36
x = 9 hours <--- Answer for the second question
It will take 9 hours to reach -1 degrees Fahrenheit.
Hope this helps!
