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wolverine [178]
4 years ago
5

How do you solve this answer

Mathematics
1 answer:
Dennis_Churaev [7]4 years ago
3 0

Answer:

i think that the inquality is true but idk the solution..

Step-by-step explanation:

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Find the sum of the first 20 terms
Dennis_Churaev [7]

Answer:20.5

Step-by-step explanation:

1.5+1.45+1.40+1.35+1.30+1.25+1.20+1.15+1.10+1.05+1.00+0.95+0.90+0.85+0.80+0.75+0.70+0.65+0.60+0.55=20.5

7 0
3 years ago
The rectangle below has an area of x^2 - 9 square meters and a width of x - 3 meters.
Rama09 [41]

Answer:

x+3

Step-by-step explanation:

Area of a rectangle is L\cdot W.

We know the width, W, is x-3 and we know the area is x^2-9.

Inputting this in our formula above we get:

x^2-9=L(x-3)

L is a an expression such that when you multiply it to (x-3) gives you (x^2-9).

x^2-9 is a difference of squares and can be factored using:

a^2-b^2=(a-b)(a+b).

x^2-9=(x-3)(x+3).

So L=x-3 and W=x+3.

4 0
3 years ago
Could you please help with this
Anon25 [30]

Answer:

40 Cubic Centimeters.

Step-by-step explanation:

V=\frac{lwh}{3}

3 0
3 years ago
Suppose that T : R3 → R2 is given by:
Ad libitum [116K]

Answer:  The required answers are

(a) T is proved to be a linear transformation.

(b) The matrix A such that T(x) = Ax is \begin{pmatrix}1 & 0 &0 \\ 0 & 1 &0 \end{pmatrix}

Step-by-step explanation:  We are given a linear transformation T : R³ → R² defined as follows :

T(a,b,c)=(a,b).

We are to

(a) prove that T is a linear transformation

and

(b) find a matrix A such that T(x) = Ax.

(a) Let s, t are any real numbers and (a, b, c), (a', b', c') ∈ R³.

Then, we have

T(s(a,b,c)+t(a',b',c'))\\\\=T(sa+ta',sb+tb',sc+tc')\\\\=(sa+ta',sb+tb')\\\\=(sa,sb)+(ta'+tb')\\\\=s(a,b)+t(a',b')\\\\=sT(a,b,c)+tT(a',b',c').

So, we get

T(s(a,b,c)+t(a',b',c'))=sT(a,b,c)+tT(a',b',c').

Therefore, T is a linear transformation.

(b) We know that B = {(1, 0, 0), (0, 1, 0), (0, 0, 1)} is a standard basis for R³ and B' = {(1, 0), (0, 1)} is a standard basis for R².

So, we have

T(1,0,0)=(1,0)=1(1,0)+0(0,1),\\\\T(0,1,0)=(0,1)=0(1,0)+1(0,1),\\\\T(0,0,1)=(0,0)=0(1,0)+0(0,1).

So, the matrix A such that T(x) = Ax will be given by

\begin{pmatrix}1 & 0 &0 \\ 0 & 1 &0 \end{pmatrix}

Thus,

(a) T is proved to be a linear transformation.

(b) The matrix A such that T(x) = Ax is  \begin{pmatrix}1 & 0 &0 \\ 0 & 1 &0 \end{pmatrix}

4 0
3 years ago
Find the least common multiple of 7 3 2
Alexus [3.1K]
The answer should be 42
5 0
3 years ago
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