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nordsb [41]
3 years ago
11

Steven is making some party favors for his birthday party. He has 96 cars and 80 game cards. He wants each party's favor to be t

he same, and he wants to use all of the cars and game cards. How many party favors can he make? How many cars and game cards will be in each bag?
Mathematics
1 answer:
Kaylis [27]3 years ago
5 0

Answer:

He can make 16 party favors.

There will be 6 cars in each bag.

There will be 5 game cards in each bag.

Step-by-step explanation:

96/16=6

80/16=5

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The average cost of a compact car at a certain dealership over the last ten years has ranged from $14,000 to $18,500. Suppose yo
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Answer:

Part (A): The scale of y: 1 interval being equal to 500 units and from 14,000 to 18,500.

Part (B): The good interval to use for the y-axis should be 1 to 10.

Step-by-step explanation:

Consider the provided information.

As we know the X axis represents the independent variable, since years are the independent variable. So, X axis represents the years.

Y axis represents the dependent variable, since average cost is dependent variable. So, Y axis represents the average cost.

Part (A) what is a good scale to use for the y-axis?

It is given that range is from $14,000 to $18,500.

So, 1 interval being equal to 500 units, so that it will suitable for 18,500.

The scale of y should be 14,000 to 18,500 as 14,000 is the starting average cost and 18,500 is the last average cost.

Part (b) what is a good interval to use for the y-axis?

The scale for x should be 1 year. As It should start from 1 to 10.

The good interval to use for the y-axis should be 1 to 10.

The required scale is shown in figure,

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3 years ago
How do you find the slope.and y-intercept of y= 1/3-2
NikAS [45]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Read 2 more answers
A​ person's blood pressure is monitored by taking 4 readings daily. The probability distribution of his reading had a mean of 13
ss7ja [257]

Answer:

a) Mean = 133, Standard deviation = 2.5

b) Normal distribution

c) 0.0026

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 4

Mean = 133

Standard deviation = 5

a) Mean and the standard deviation of the sampling distribution of the sample mean for the four observations each day.

The sampling distribution has a mean equal to the population mean

\bar{x} = \mu = 133

The standard deviation of the sampling distribution is given by:

\sigma_s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{5}{\sqrt{4}} = 2.5

b) Shape of the sampling​ distribution

Central limit theorem:

When a large sample is drawn from a normal distribution, then the distribution of sample means approaches a normal distribution.

Since the distribution is normal,  the sampling distribution of the sample mean will be bell shaped and follow a normal distribution.

c) P(sample mean exceeds 140)

P( x > 140) = P( z > \displaystyle\frac{140 - 133}{2.5}) = P(z > 2.8)

= 1 - P(z \leq 2.8)

Calculation the value from standard normal z table, we have,  

P(x > 140) = 1 - 0.9974 = 0.0026

0.0026 is the probability that the sample mean exceeds 140.

6 0
3 years ago
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