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2 years ago

11

If x = 11 units and h = 7 units, then what is the area of the triangle shown?

2 answers:

m_a_m_a [10]2 years ago

3 0

The answer is A because of base times height

STatiana [176]2 years ago

3 0

Answer:

38.5

Step-by-step explanation:

x÷2= 5.5

5.5×7= 38.5

answer: 38.5

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A polygon is regular if each of its sides has the same length. Find the perimeter of the regular polygon. #36

vazorg [7]

Take the length of one of the sides and times that by the radius. Divide that answer by 2. Now take that and multiply by the number of sides the polygon has. If you can't find the radius or side, you're going to have to use tan, sin, or cos.

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3 years ago

Will give brainlist whoever asks correctly

Semenov [28]

Answer:

The answer is B.-3/2

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Step-by-step explanation:

I use $\frac{rise}{run}$

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2 years ago

Pls help will give Brainlyist

kvasek [131]

Answer:

B

Step-by-step explanation:

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2 years ago

The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i

kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

$S=\pi r\sqrt{r^2+h^2}$

and volume,

$V=\frac{1}{3}\pi r^2 h$

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

$f(r,h)=\frac{1}{3}\pi r^2 h$

subject to,

$g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)$

We know for maximum volume $r\neq 0$ . So let $\lambda$ be the Lagranges multipliers be such that,

$f_r=\lambda g_r$

$\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)$

And,

$f_h=\lambda g_h$

$\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}$

$\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)$

Substitute (3) in (2) we get,

$\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)$

$\implies h^2=2r^2$

Substitute this value in (1) we get,

$\pi r\sqrt{h^2+r^2}=8$

$\implies \pi r \sqrt{2r^2+r^2}=8$

$\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252$

Then,

$h=\sqrt{2}(1.21252)\equiv 1.71476$

Hence largest volume,

$V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114$

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2 years ago

5. Estimate the value of √150 O between 5 and 6 O between 6 and 7 O between 7 and 8 O between 8 and 9

Digiron [165]

Answer:

basicaly your asking to be fulled so {{64

Step-by-step explanation:

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2 years ago