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3 years ago

Expand and simplify 3(x+2)+2(x-1)

Mathematics

1 answer:

Fittoniya [83]3 years ago

7 0

3(x + 2) + 2(x - 1)
3(x) + 3(2) + 2(x) - 2(1)
3x + 6 + 2x - 2
3x + 2x + 6 - 2
5x + 4

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A quadratic equation ax^2+bx+c=0 has -11 and 4 as solutions. Find the values of b and c if the value of a is 1 (hint, use zero f

Alina [70]

Answer:

b = 7, c = -44

Step-by-step explanation:

If the quadratic equation has the solutions -11 and 4, the two factors are:

$(x+11)(x-4)=0$

Since when we use the zero factor property we get

x+11=0 ⇒ x= -11

x-4=0 ⇒ x=4

Thus, we have used the zero factor property in reverse to find the factorization of the quadratic equation.

Now we develop the multiplications between parenthesis:

$(x+11)(x-4)=0\\x^2-4x+11x-44=0\\x^2+7x-44=0$

So b is the number that accompanies the x: b = 7

and c is the independent number: c = -44

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3 years ago

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swat32

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3 years ago

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