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3 years ago

What procedure can be used to solve the equation StartFraction x Over 19.3 EndFraction = 38.6, and what is the solution?

Mathematics

2 answers:

kozerog [31]3 years ago

3 0

Answer: it’s number D I think let me know if I’m wrong

Step-by-step explanation:

Arada [10]3 years ago

3 0

Answer:

the answer is d.Multiply both sides by 19.3; the solution is 744.98.

Step-by-step explanation:

got it right on edge.

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Using induction, verify the inequality. (1 + x)" ? 1 + nx, for x ?-1 and ? 1

klio [65]

Answer with explanation:

The Inequality should be:

$(1+x)^n\geq 1+n x$

Where, n and x are any integers.

⇒For, x= -1

L HS

$=[1+(-1)]^n\\\\=(0)^n\\\\=0$

R HS

→1+n × (-1)

=1-n

If, n is any Integer, then for, n=1

1-1=0

For, n=2

1-2= -1

....

So, $(1+x)^n\geq 1+n x$

for, x=-1.

⇒For, x=1

L HS

$=[1+(1)]^n\\\\=(2)^n$

For, n=1

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For, =2

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R HS

→1+n × (1)

=1+n

If, n is any Integer, then for, n=1

1+1=2

For, n=2

1+2= 3

....

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3 0

3 years ago

What percent of 15 is 12

creativ13 [48]

12/15= x

.8=x

.8 times 100

12 out of 15 is 80 %

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4 years ago

A cooler has 12 apple juices and 15 grape juices. 9 of the apple juices are sugar free and 5 of the grape juices are sugar free.

Alexus [3.1K]

A - juice is not sugar free

B - juice is not grape juice

$|\Omega|=27\\ |A|=13\\ |A\cap B|=3\\\\ P(A)=\dfrac{13}{27}\\ P(A\cap B)=\dfrac{3}{27}=\dfrac{1}{9}\\\\ P(B|A)=\dfrac{\dfrac{1}{9}}{\dfrac{13}{27}}=\dfrac{1}{9}\cdot\dfrac{27}{13}=\dfrac{3}{13}$

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Citrus2011 [14]

I think the answer is B

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