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prisoha [69]
3 years ago
12

A rectangular field is 125 yards long and the length of one diagonal of the field is 150 yards. What is the width of the field?

Mathematics
1 answer:
Artemon [7]3 years ago
6 0
Dhdhjdjsjskcbfjfjfdjdjjejwie
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Bee + ant= 10, ant - bee = 8, ant × bee= ?
Alona [7]

The Correct Answer Is...

<em><u>9.</u></em>

Any Questions? Comment Below!

<em><u>-AnonymousGiantsFan</u></em>

7 0
3 years ago
A bad punter on a football team kicks a football approximately straight upward with an initial velocity of 89 ft/sec.
Andrej [43]

Answer:

See below

Step-by-step explanation:

Vertical velocity will be affected by gravity in this scenario

df = do + vo t + 1/2 a t^2         do = original height = 4 ft      a = -32.2 ft/s^2

<u>df = 4 + 89 t  - 1/2 (32.2) t^2        df = height</u>

<u />

On the way up and the way down, the ball may reach height of 102.2125 ft :

102.2125 = 4 + 89 t - 1/2 (32.2) t2   re-arrange to:

-16.1 t^2 + 89t - 98.2125 =0  

      Use Quadratic Formula to find <u>t =   1.5 and 4.0 s </u>

6 0
2 years ago
​Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.
Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

x^{3}+7 x^{2}+12 x=0

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

x^{3}+7 x^{2}+12 x=0

x\left(x^{2}+7 x+12\right)=0   ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

x^{2}+7 x+12=0

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

<em><u>Therefore, the two roots are:</u></em>

\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0
3 years ago
At what interest rate must you invest $4500 to have $7,000 after 6 years, if the interest is compounded quarterly?
labwork [276]

Answer:

The amount is $8358.7 and the interest is $3858.7.

Step-by-step explanation:

Explanation

STEP 1: To find amount we use formula:

A=P(1+rn)n⋅t

A = total amount

P = principal or amount of money deposited,

r = annual interest rate

n = number of times compounded per year

t = time in years

In this example we have

P=$4500 , r=7% , n=2 and t=9 years

After plugging the given information we have

AAAA=4500(1+0.072)2⋅9=4500⋅1.03518=4500⋅1.857489=8358.7

STEP 2: To find interest we use formula A=P+I, since A=8358.7 and P = 4500 we have:

A8358.7II=P+I=4500+I=8358.7−4500=3858.7

4 0
3 years ago
What the correct answer
Dvinal [7]

Its ‘B’

100% sure

Plz mark me brainliest

4 0
3 years ago
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