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3 years ago

13

What does 5+9999 equal?

1 answer:

Gwar [14]3 years ago

5 0

Hope this isnt a trick question 10,004

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A pebble drops from a balcony that is 160 feet above the ground. The pebble lands on the top of a sign that is 16 feet high. The

MA_775_DIABLO [31]

Answer:

3 seconds

Step-by-step explanation:

16 = 160 - 16t²

16t² = 144

t² = 9

t = 3

7 0

3 years ago

Simplify this expression<br> 4x(7x^2)<br> A 11x^2<br> B. 28x^2<br> C. 11x^3<br> D. 28x^3

slega [8]

Answer:

28 x^3

Step-by-step explanation:

4x(7x^2)

4 * x* 7* x*x

4*7 x*x*x

28 x^3

7 0

3 years ago

Read 2 more answers

Use (<,>,=) to compare 2/3 and 3/4

lina2011 [118]

2/3 < 3/4. Hope that helps

3 0

3 years ago

What two numbers have an absolute value of 16

Harrizon [31]

Both the negative and positive counterparts of a number have the same absolute value, or distance from 0.

The two numbers are 16 and -16.
They both have the same absolute value, 16.

7 0

3 years ago

Read 2 more answers

On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)

xz_007 [3.2K]

Answer:

$P = 10 + 2\sqrt{53}$ units

Step-by-step explanation:

Given

Shape: Kite WXYZ

W (-3, 3), X (2, 3),

Y (4, -4), Z (-3, -2)

Required

Determine perimeter of the kite

First, we need to determine lengths of sides WX, XY, YZ and ZW using distance formula;

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

For WX:

$(x_1, y_1)\ (x_2,y_2) = (-3, 3),\ (2, 3)$

$WX = \sqrt{(-3 - 2)^2 + (3 - 3)^2}$

$WX = \sqrt{(-5)^2 + (0)^2}$

$WX = \sqrt{25}$

$WX = 5$

For XY:

$(x_1, y_1)\ (x_2,y_2) = (2, 3)\ (4,-4)$

$XY = \sqrt{(2 - 4)^2 + (3 - (-4))^2}$

$XY = \sqrt{-2^2 + (3 +4)^2}$

$XY = \sqrt{-2^2 + 7^2}$

$XY = \sqrt{4 + 49}$

$XY = \sqrt{53}$

For YZ:

$(x_1, y_1)\ (x_2,y_2) = (4,-4)\ (-3, -2)$

$YZ = \sqrt{(4 - (-3))^2 + (-4 - (-2))^2}$

$YZ = \sqrt{(4 +3)^2 + (-4 +2)^2}$

$YZ = \sqrt{7^2 + (-2)^2}$

$YZ = \sqrt{49 + 4}$

$YZ = \sqrt{53}$

For ZW:

$(x_1, y_1)\ (x_2,y_2) = (-3, -2)\ (-3, 3)$

$ZW = \sqrt{(-3 - (-3))^2 + (-2 - 3)^2}$

$ZW = \sqrt{(-3 +3)^2 + (-2 - 3)^2}$

$ZW = \sqrt{0^2 + (-5)^2}$

$ZW = \sqrt{0 + 25}$

$ZW = \sqrt{25}$

$ZW = 5$

The Perimeter (P) is as follows:

$P = WX + XY + YZ + ZW$

$P = 5 + \sqrt{53} + \sqrt{53} + 5$

$P = 5 + 5 + \sqrt{53} + \sqrt{53}$

$P = 10 + 2\sqrt{53}$ units

6 0

3 years ago