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GuDViN [60]
3 years ago
15

Average speed of Car 1 = 35 mph. Average speed of Car 2 = 55 mph. Time elapsed between start of Car 1 and start of Car 2 = 18 mi

nutes.
How long before Car 2 overtakes Car 1? ___________ hour.
Mathematics
2 answers:
Anna [14]3 years ago
5 0

Answer:

.525

Step-by-step explanation:

35(t+18/60) = 55t

35t +10.5 = 55t  

10.5 = 20t

0.525 = t

maxonik [38]3 years ago
3 0
It should be after 6 hours
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What is the measure of angle X?_
horrorfan [7]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
NEED HELP SOON!!!!<br> for any numbers a, b, and c, a(b + c)=ab+ac
navik [9.2K]

The property displayed here is the distributive property.

If you have a variable or unknown number inside or outside of parentheses, you can distribute it to each term and add the terms together, and it will remain true.

Example:

4(x + 5)

After distributing, it'll look like this:

4x + 20


6 0
3 years ago
A mechanic gives a survey to all of his customers asking them to rate the quality of the service they received. He then keeps tr
topjm [15]

Answer:

Some customers who rate their service as high quality return for additional services.

Step-by-step explanation:

Last year, the results showed that of the customers who reported high quality service, 20% returned for additional services.

This shows than some customers are satisfied overall and return back for additional services.

6 0
3 years ago
What is 7 times the sum of a squared and b minus 4 times the sum of a squared and b
spayn [35]
<span><span>The sum of a squared and b is given by
a^2+b

</span>7 times the sum of a squared and b is given by
</span><span>7(a^2+b)
while 4 times the sum of a squared and b is given by
</span>4(a^2+b)

Therefore, <span>7 times the sum of a squared and b minus 4 times the sum of a squared and b is given by

7(a^2+b)-4(a^2+b)=3(a^2+b)</span>
7 0
3 years ago
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