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GuDViN [60]
3 years ago
15

Average speed of Car 1 = 35 mph. Average speed of Car 2 = 55 mph. Time elapsed between start of Car 1 and start of Car 2 = 18 mi

nutes.
How long before Car 2 overtakes Car 1? ___________ hour.
Mathematics
2 answers:
Anna [14]3 years ago
5 0

Answer:

.525

Step-by-step explanation:

35(t+18/60) = 55t

35t +10.5 = 55t  

10.5 = 20t

0.525 = t

maxonik [38]3 years ago
3 0
It should be after 6 hours
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Fill in the blanks to make true number sentences.<br><br> 1 3/5 = __ : __
arsen [322]

Answer:

1 6/10

Step-by-step explanation:

you should first turn this fraction into a improper fraction

1 3/5= 8/5

now you multiply the denominator and the numerator by the same number, in this case i am using 2

8/5 times 2/2= 16/10 or 1 6/10  

6 0
3 years ago
Find the degree of the polynomial: a^3+3a^2−5a
emmainna [20.7K]

Answer:

The degree of the polynomial is 3

Step-by-step explanation:

Given:

a^3+3a^2-5a

To Find:

The degree of the polynomial= ?

Solution:

The degree of the polynomial   is the value of the greatest exponent of any expression (except the constant ) in the polynomial. To find the degree all that you have to do is find the largest exponent in the polynomial

Here in the given polynomial

a^3+3a^2- 5a

The terms are

a^3

3a^2

5a

The term  a^3 has  the largest exponent of  3

Note:  The degree of the polynomial does not depend  on coefficients of the terms

3 0
3 years ago
If the radius of a coin is 20cm ,find its surface area.​
jasenka [17]

Answer:

It's surface area is 1257.14cm^2

Step-by-step explanation:

area=22/7×20cm×20cm

=3.14×20cm×20cm

=1257.14cm^2

4 0
3 years ago
Owning a small and successful business isn't easy! There is a monthly cost of shipping
galben [10]

nwere ike nwa osisi poop pusi ibu onu nkita meow n'anya papa 46721

8 0
3 years ago
Jimmy set his score for his math test. After the math teacher returnee his paper to him, he realized that if he increased his ta
mixer [17]
When ever you have percentages, it should be helpful to bear in mind you can express them as multipliers. In this case, it will be helpful.
So, if we let:
a = test score
b = target score
then, using the information given:
a = 1.1b + 1
a = 1.15b - 3
and we get simultaneous equations.
'1.1' and '1.15' are the multipliers that I got using the percentages. Multiplying a value by 1.1 is the equivalent of increasing the value by 10%. If you multiplied it by 0.1 (which is the same as dividing by 10), you would get just 10% of the value.
Back to the simultaneous equations, we can just solve them now:
There are a number of ways to do this but I will use my preferred method:
Rearrange to express in terms of b:
a = 1.1b + 1
then b = (a - 1)/1.1
a = 1.15b - 3
then b = (a + 3)/1.15
Since they are both equal to b, they are of the same value so we can set them equal to each other and solve for a:
(a - 1)/1.1 = (a + 3)/1.15
1.15 * (a - 1) = 1.1 * (a + 3)
1.15a - 1.15 = 1.1a + 3.3
0.05a = 4.45
a = 89

8 0
3 years ago
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