Answer:
h = 6
Step-by-step explanation:
Given the 2 equations
- 3x + 4y = - 30 → (1)
9x + 5y = 39 → (2)
We require the value of the x- coordinate at the point of intersection, thus require to eliminate the y- term from the equations
Multiply (1) by 5 and (2) by - 4
- 15x + 20y = - 150 → (3)
- 36x - 20y = - 156 → (4)
Add (3) and (4) term by term thus eliminating y
- 51x = - 306 ( divide both sides by - 51 )
x = h = 6
Answer: d
Step-by-step explanation: when you bring 3 into the square root, it becomes isqrt(63). when you apply i, it makes the number sqrt(-63)
pretty sure I did it right this time
Answer:
-1.25x-5
Step-by-step explanation:
Check the picture below.
so the area of the hexagon is really just the area of two isosceles trapezoids.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ a=2\\ b=4\\ h=2 \end{cases}\implies \begin{array}{llll} A=\cfrac{2(2+4)}{2}\implies A=6 \\\\\\ \stackrel{\textit{twice that much}}{2A = 12} \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D2%5C%5C%20b%3D4%5C%5C%20h%3D2%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B2%282%2B4%29%7D%7B2%7D%5Cimplies%20A%3D6%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwice%20that%20much%7D%7D%7B2A%20%3D%2012%7D%20%5Cend%7Barray%7D)
Answer:
Im sure that the answer is c
