Verify whether the point (2,5) lies on 2x -y+1=0 or not

Mathematics

1 answer:

Ksenya-84 [330]2 years ago

3 0

Answer:

yes verified

Step-by-step explanation:

2x-y+1=0

substitute

2(2)-5+1=(0?)

4-5+1=0

yes

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1) x² 2(x+y) - y^2 <br>2) x^4+ x^2y^2+ y^4

spin [16.1K]

Answer: 1) Let's simplify step-by-step.

x22(x+y)−y2

Distribute:

=(x22)(x)+(x22)(y)+−y2

=x23+x22y+−y2

Answer:

=x23+x22y−y2

2)Let's simplify step-by-step.

x4+x2y2+y4

There are no like terms.

Answer:

=x4+x2y2+y4

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3 years ago

If (x)=3x-1 and s(x)=2x+1, which expression is equivalent to r over s (6) ?

katrin [286]

Answer:

$\large\boxed{\dfrac{3(6)-1}{2(6)+1}}$

Step-by-step explanation:

$\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\\text{We have}\\\\f(x)=3x-1,\ g(x)=2x+1\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{3x-1}{2x+1}\\\\\left(\dfrac{f}{g}\right)(6)\to\text{put x = 6 to the equation of the function}\ \left(\dfrac{f}{g}\right)(x):\\\\\left(\dfrac{f}{g}\right)(6)=\dfrac{3(6)-1}{2(6)+1}$