Answer:
D. $0, $20, $90
Step-by-step explanation:
If X represents the amount you win, then possible outcomes for X are $0, $20, and $90.
Answer:
Heights of 29.5 and below could be a problem.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.
This means that 
There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.
Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus


Heights of 29.5 and below could be a problem.
Answer:
, 12,
, 10
Step-by-step explanation:



so
= 10
12
= 10.66
and 10
Because saying 5 over 1/2 is saying 5 divided by 1/2 which is the same as saying 5 * 2
8 over 3/4 is 8 divided by 3/4 which is 8 * 1.33.
A fraction is division. If you mean 5 and 1/2 as well as 8 and 3/4 then remove 5 and 1/2 from the answer.
Answer:
1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.
Step-by-step explanation:
The order in which the teachers are chosen is not important, which means that the combinations formula is used to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.
In this question:
1 from a set of 2(Either Mrs. Vera or Mr. Jan).
3 from a set of 18 - 2 = 16. So

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.
Answer:
98
Step-by-step explanation: