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3 years ago

Please answer (NO SPAMMING) What is the sum of 56.4t + 1650kg? Give your answer in Kg

Mathematics

2 answers:

Aliun [14]3 years ago

7 0

Answer:1,706

Step-by-step explanation:

Add

kenny6666 [7]3 years ago

4 0

Answer:

58,050,000 grams= 58050kg

Step-by-step explanation:

58059kg is the answer

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Solve by quadratic equation

Ymorist [56]

<h2>Question :</h2>

$\tt \dfrac{x+2}{x-2} + \dfrac{x-2}{x+2} = \dfrac{5}{6}$

<h2>Answer :</h2>

$\large \underline{\boxed{\bf{x = \dfrac{\pm 2\sqrt{119}}{7}}}}$

<h2>Explanation :</h2>

$\tt : \implies \dfrac{x+2}{x-2} + \dfrac{x-2}{x+2} = \dfrac{5}{6}$

$\tt : \implies \dfrac{(x+2)(x+2) + (x-2)(x-2)}{(x-2)(x+2)} = \dfrac{5}{6}$

$\tt : \implies \dfrac{(x+2)^{2} + (x-2)^{2}}{(x-2)(x+2)} = \dfrac{5}{6}$

<u>Now, we know that</u> :

$\large \underline{\boxed{\bf{(a+b)^{2} = a^{2} + b^{2}+ 2ab}}}$
$\large \underline{\boxed{\bf{(a-b)^{2} = a^{2} + b^{2} - 2ab}}}$
$\large \underline{\boxed{\bf{(a+b)(a-b) = a^{2} - b^{2}}}}$

$\tt : \implies \dfrac{x^{2}+2^{2}+ 2 \times x \times 2 + x^{2}+2^{2} - 2 \times x \times 2 }{x^{2}-2^{2}} = \dfrac{5}{6}$

$\tt : \implies \dfrac{x^{2}+ 4 + \cancel{4x} + x^{2}+ 4 - \cancel{4x}}{x^{2}-4} = \dfrac{5}{6}$

$\tt : \implies \dfrac{x^{2} + x^{2} + 4 + 4}{x^{2}-4} = \dfrac{5}{6}$

$\tt : \implies \dfrac{2x^{2} + 8}{x^{2}-4} = \dfrac{5}{6}$

<u>By cross multiply</u> :

$\tt : \implies (2x^{2} + 8)6= 5(x^{2}-4)$

$\tt : \implies 12x^{2} + 48 = 5x^{2}-20$

$\tt : \implies 12x^{2} + 48 - 5x^{2} + 20 = 0$

$\tt : \implies 7x^{2} + 68 = 0$

$\tt : \implies 7x^{2} + 0x + 68 = 0$

<u>Now, by comparing with ax² + bx + c = 0, we have</u> :

a = 7
b = 0
c = 68

<u>By using quadratic formula</u> :

$\large \underline{\boxed{\bf{x = \dfrac{-b \pm \sqrt{b^{2} - 4ac}}{2a}}}}$

$\tt : \implies x = \dfrac{-(0) \pm \sqrt{(0)^{2} - 4(7)(68)}}{2(7)}$

$\tt : \implies x = \dfrac{0 \pm \sqrt{0 - 1904}}{14}$

$\tt : \implies x = \dfrac{\pm \sqrt{- 1904}}{14}$

$\tt : \implies x = \dfrac{\pm \sqrt{2\times 2\times 2\times 2\times 7\times 17}}{14}$

$\tt : \implies x = \dfrac{\pm \cancel{2} \times 2\sqrt{7\times 17}}{\cancel{14}}$

$\tt : \implies x = \dfrac{\pm2\sqrt{119}}{7}$

$\large \underline{\boxed{\bf{x = \dfrac{\pm 2\sqrt{119}}{7}}}}$

Hence value of $\bf x =\dfrac{\pm 2\sqrt{119}}{7}$

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3 years ago

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exis [7]

Answer:

Step-by-step explanation:

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3 years ago

What is the I-value of the solution of the system of equatIons <br> x + 3y = 13 and 3x - y = –11?

Marrrta [24]

Answer:x=1,y=

Step-by-step explanation:Here's one of many ways of solving this system. Since we are already told that

−

from the first equation, just plug in

−

everywhere you see an

in the second equation.

So the second equation becomes

(

−

)

. Solve this for

to get

Then, go back to the first equation that says

−

and plug in

. So

Check your work by plugging in the values.

−

and

(

)

, so we are right.

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3 years ago

The weights of 5 girls are 70 pounds, 68 pounds, 85 pounds, 62 pounds, and 70 pounds. Nina finds measures of center and measures

Anestetic [448]

Answer:

<h2>360 I'm sure that's is answer thank you po</h2>

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2 years ago

Find an equation for the nth term of the arithmetic sequence.

mezya [45]

Answer:

$a_n=-15+9(n-1)$

Step-by-step explanation:

The terms of the arithmetic sequence are...

-15, -6, 3, 12, ...

The first term is

a_1=-15

The common difference is

$d=-6--15=9$

The equation for the nth term is given by;

$a_n=a_1+(n-1)d$

We substitute the values into the formula to get;

$a_n=-15+9(n-1)$

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3 years ago

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