How do you find the percent of a number

2 answers:

7 0

To find the percent of a number, just turn the percentage into a decimal. To do that just go 2 decimal places to the left. For example, 25% becomes 0.25. Then, just multiply that decimal by the number you're finding the percentage of. That's it!

Ex. Find 50% of 10

50% becomes 0.5
0.5(10)= 5

50% of 10 is 5.

natulia [17]3 years ago

3 0

You set up a proportion. first, put the percent so if it's 30 percent, it would be 30 over 100. Then, set up the second part. is over of.

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Leah cut a 7 inch ribbon into pieces that are 1/2 an inch long. How many pieces of ribbon did she cut?

photoshop1234 [79]

14 ribbons.

7 divided by 1/2 is 14. dividing by a fraction or decimal is just like multiplying without the decimal point or numerator.

7 0

3 years ago

In how many ways can you spell the word ROOM in the grid below? You can start on any letter R, then on each step you can step on

Zina [86]

Answer:

84? Not sure but pretty sure

Step-by-step explanation:

In a straight line, the word can only be spelled on the diagonals, and there are only two diagonals in each direction that have 2 O's.

If 90° and reflex turns are allowed, then the number substantially increases.

Corner R: can only go to the adjacent diagonal O, and from there to one other O, then to any of the 3 M's, for a total of 3 paths.

2nd R from the left: can go to either of two O's, one of which is the same corner O as above. So it has the same 3 paths. The center O can go to any of 4 Os that are adjacent to an M, for a total of 10 more paths. That's 13 paths from the 2nd R.

Middle R can go the three O's on the adjacent row, so can access the three paths available from each corner O along with the 10 paths available from the center O, for a total of 16 paths.

Then paths accessible from the top row of R's are 3 +10 +16 +10 +3 = 42 paths. There are two such rows of R's so a total of 84 paths.

6 0

3 years ago

Read 2 more answers

What is the length of line segment KJ?

Karolina [17]

Please consider the attached file.

We can see that triangle JKM is a right triangle, with right angle at M. Segment KM is 6 units and segment MJ is 3 units. We can also see that KJ is hypotenuse of right triangle.

We will use Pythagoras theorem to solve for KJ as:

$KJ^2=KM^2+MJ^2$