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3 years ago

How do you find the percent of a number

2 answers:

7 0

To find the percent of a number, just turn the percentage into a decimal. To do that just go 2 decimal places to the left. For example, 25% becomes 0.25. Then, just multiply that decimal by the number you're finding the percentage of. That's it!

Ex. Find 50% of 10

50% becomes 0.5
0.5(10)= 5

50% of 10 is 5.

natulia [17]3 years ago

3 0

You set up a proportion. first, put the percent so if it's 30 percent, it would be 30 over 100. Then, set up the second part. is over of.

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-5/6x-7/30x+1/5x-52 please help me guys cuz imk not good with math

Marina CMI [18]

Answer:

$\frac{-13}{15} x-52$

Step-by-step explanation:

$\frac{-5}{6}x-\frac{7}{30}x+\frac{1}{5}x-52$

$=\frac{-5}{6}x+\frac{-7}{30}x+\frac{1}{5}x+-52$

Combine Like Terms:

$=\frac{-5}{6}x+\frac{-7}{30}x+\frac{1}{5}x+-52$

$=(\frac{-5}{6}x+\frac{-7}{30}x+\frac{1}{5}x)+(-52)$

$=\frac{-13}{15}x+-52$

Therefore, $\frac{-13}{15}x+-52$ will be your final answer.

7 0

3 years ago

To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data

nexus9112 [7]

Answer:

a) $\sigma = 0.167$

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of $\mu$ . So $X - \mu = 0.5$ must have $Z = 3$ and $X - \mu = -0.5$ must have $Z = -3$ .

$Z = \frac{X - \mu}{\sigma}$

$3 = \frac{0.5}{\sigma}$

$3\sigma = 0.5$

$\sigma = \frac{0.5}{3}$

$\sigma = 0.167$

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that $\sigma = 2.8$