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2 years ago

Question 5 Multiple Choice Worth 4 points)

Mathematics

1 answer:

tia_tia [17]2 years ago

3 0

Answer:

Step-by-step explanation:

The y-intercept is the line that crosses the y axis on the gragh

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Please help me :)) algebra 2! what are the real roots?

irina1246 [14]

Answer:

Step-by-step explanation:

So we have the equation:

$3(x-4)^\frac{4}{3}+16=64$

First, let's subtract 16 from both sides:

$3(x-4)^\frac{4}{3}=48$

Now, let's divide both sides by 3:

$(x-4)^\frac{4}{3}=16$

Remember that with fractional exponents, we can move the denominator into the root position. Therefore:

$(\sqrt[3]{x-4})^4=16$

Let's take the fourth root of both sides. Since we're taking an even root, make sure to have the plus-minus symbol!

$\sqrt[3]{x-4} =\pm 2$

Cube both sides. Since we're cubing, the plus-minus stays.

$x-4=\pm 8$

Add 4 to both sides.

$x=\pm 8+4$

Calculator:

$x=8+4\text{ or } x=-8+4\\x=12\text{ or } x=-4$

So, our answer is A.

And we're done!

7 0

3 years ago

If you draw a card with a value of 4 or less from a standard deck of cards, I will pay you 165$ if not your pay me $45. (Aces ar

jekas [21]

Answer: The required expected value is $3.46.

Step-by-step explanation:

Since we have given that

Number of value of 4 or less are

2,3,4

So, there are 12 in numbers.

So, probability would be

$\dfrac{12}{52}$

Since Aces are considered as the highest card in the deck.

So, remaining probability would be

$\dfrac{40}{12}$

Amount paid or value of 4 or less = $165

Amount not paid for other case = $45

So, the expected value would be

$\dfrac{12}{52}\times 165-\dfrac{40}{52}\times 45\\\\=\dfrac{1980}{52}-\dfrac{1800}{52}\\\\=\dfrac{180}{52}\\\\=3.46$

Hence, the required expected value is $3.46.

7 0

2 years ago

The physical plant at the main campus of a large state university receives daily requests to replace fluorescent light bulbs. Th

ankoles [38]

We have been given that the distribution of the number of daily requests is bell-shaped and has a mean of 38 and a standard deviation of 6. We are asked to find the approximate percentage of lightbulb replacement requests numbering between 38 and 56.

First of all, we will find z-score corresponding to 38 and 56.

$z=\frac{x-\mu}{\sigma}$

$z=\frac{38-38}{6}=\frac{0}{6}=0$

Now we will find z-score corresponding to 56.

$z=\frac{56-38}{6}=\frac{18}{6}=3$

We know that according to Empirical rule approximately 68% data lies with-in standard deviation of mean, approximately 95% data lies within 2 standard deviation of mean and approximately 99.7% data lies within 3 standard deviation of mean that is $-3\sigma\text{ to }3\sigma$ .