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3 years ago

3/4 of a number is 27. What's the number?

Mathematics

2 answers:

Mice21 [21]3 years ago

8 0

Answer:

Step-by-step explanation:

german3 years ago

6 0

Answer:

do 27/3 and multiply that by 4 to get 36

Step-by-step explanation:

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The sides of the pentagon are consecutive even integers. Find the length of the shortest side if the second longest side is 24%

Digiron [165]

Answer:

Please see the image for solution

Step-by-step explanation:

5 0

4 years ago

What is the volume of the prism? (Easy ig)

motikmotik

Answer:

Volume = 42 in.²

Step-by-step explanation:

Volume of the triangular prism = ½×b×h×l

where,

b = 4 in.

h = 3 in.

l = 7 in.

Plug in the values

Volume = ½ × 4 × 3 × 7

Volume = 42 in.³

6 0

3 years ago

Find the length of the missing side. Give your answer in the simplest radical form.

taurus [48]

Answer:

x = $2\sqrt{5}$

Step-by-step explanation:

Use Pythagorean theorem,

Hypotenuse² = base² + altitude²

x² = (√8)² + 4²

= 8 + 16

= 20

x = √20 = $\sqrt{2*2*5} = 2\sqrt{5}$

x = $2\sqrt{5}$

6 0

3 years ago

Find the slope of the line

alukav5142 [94]

Answer:

-4/3

Step-by-step explanation:

y2 - y1 / x2 - x1

-9 - (-1) / 0 - (-6)

-4/3

7 0

3 years ago

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

4 years ago