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patriot [66]
3 years ago
7

Evaluate the expression -5(-2)-3(-4) answer this and you will be famous on tiktok

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
7 0

Answer:

120?

Step-by-step explanation:

-5 times -2 equals 10 (since a negative times negative equals positive)

10 times -3 equals -30

-30 times -4 equals 120

Hope this helps.

Note: this may be incorrect

ANTONII [103]3 years ago
6 0

Answer:

120

Step-by-step explanation:

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Sergio passes by a bike store on Monday and sees his dream bike in the window. It cost 120 . He passes by on Wednesday and is th
insens350 [35]

Answer:

90

Step-by-step explanation:

120 - (120/4)

120 - 30 = 90

3 0
3 years ago
Help me on 12 and 13 please and fast
lys-0071 [83]

Answer:

12. B ,  13. 4

Step-by-step explanation:

12.  \frac{3}{12}+\frac{1}{12}  +\frac{2}{12} =\frac{6}{12} =\frac{1}{2}  \\13. 5-(\frac{2}{10} *5)=4

3 0
4 years ago
5. As shown in the diagram below, the angle of elevation from a point on the ground
xxMikexx [17]

Answer:

13.5

Step-by-step explanation:

This is a very simple question

tan 34 + t

             -

            20

t =13.5

6 0
3 years ago
Solve the equation for the red variable(C)in R-C=P
BARSIC [14]

If you want to solve the equation

R-C=P

for C, you can work like this: subtract P from both sides:

R-C-P = 0

Add C to both sides:

R-P=C

5 0
4 years ago
A pair of tow trucks are pulling on a trailer that is stuck
Varvara68 [4.7K]

Answer:

R=10,244 Lb

Step-by-step explanation:

In order to solve this problem, we can start by drawing the situation. (See attached picture).

We can look at the forces applied by the trucks as vectors, so in this case, in order to find the resultant force, we can add the two vectors. You can do so by drawing one force after the other and join the start of the first force with the end of the second force to form a triangle. The missing side will be the resultant force. In that triangle I drew there, the inner angle will be found by subtracting 180°-110°=70°

In this case we can find the resultant force by using the law of cosines:

A^{2}=B^{2}+C^{2}-2AB cos \alpha

so we can use the data given by the problem:

R^{2}=T_{1}^{2}+T_{2}^{2}-2T_{1}T_{2} cos \alpha

so we can solve this for R, so we get:

R=\sqrt{T_{1}^{2}+T_{2}^{2}-2T_{1}T_{2} cos \alpha}

now we can substitute:

R=\sqrt{(10,000Lb)^{2}+(7,500Lb)^{2}-2(10,000Lb)(7,500Lb) cos (70^{0})}

which yields:

R=10,244Lb

8 0
3 years ago
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