Answer:
A) The fraction of sum of money did each child receive is 
B) The sum of money did Jeff have $ 3200
Step-by-step explanation:
Given as :
Let The sum of money did Jeff have = $ x
The fraction of money did Jeff's wife get = 
of $ x
The remaining money Jeff will have = $ x - of $ x
I.e The remaining money Jeff will have = 
= 
A ) The remaining amount of money is divided equally among 4 children
So, The fraction of sum of money did each child receive = 
I.e The fraction of sum of money did each child receive =
B ) If each child will receive $ 600
∴, = $ 600
Or, 3 x = $ 600 × 16
Or, 3 x = $ 9600
∴ x = 
I.e x = $ 3200
So, The sum of money did Jeff have $ 3200
Hence ,
A) The fraction of sum of money did each child receive is
B) The sum of money did Jeff have $ 3200 Answer
We conclude that the sum of the first 8 terms of the arithmetic sequence is 17/5.
<h3>
How to get the sum of the first 8 terms?</h3>
In an arithmetic sequence, the difference between any two consecutive terms is a constant.
Here we know that:
There are 7 times the common difference between these two values, so if d is the common difference:
Then the sum of the first 8 terms is given by:
So we conclude that the sum of the first 8 terms of the arithmetic sequence is 17/5.
If you want to learn more about arithmetic sequences:
brainly.com/question/6561461
#SPJ1
Answer:
The population can be greater than 6,100 but less than 6,300, and thus, we cannot determine if the population of Farmersville will be greater than 6,300 in 2012.
Step-by-step explanation:
Inequality for the population of Farmsville:
The inequality for the population of Farmsville in x years after 2010 is given by:
Will the population of Farmersville be greater than 6,300 in 2012?
2012 is 2012-2010 = 2 years after 2010, so we have to find y(2).
The population can be greater than 6,100 but less than 6,300, and thus, we cannot determine if the population of Farmersville will be greater than 6,300 in 2012.
Answer:
that is funny. That is where my dad was born and now he has horrible breathing issues
Step-by-step explanation:
