Which expressions are equivalent to the on below select all that apply 9x

Mathematics

2 answers:

s2008m [1.1K]2 years ago

8 0

Answer:

B + D

Step-by-step explanation:

Serga [27]2 years ago

5 0

Answer:

B and D

Step-by-step explanation:

Multiplying exponents just adds them.

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6/N = 100/75<br> What is N?

ExtremeBDS [4]

The answer for this question is 4.5

7 0

2 years ago

Karen is 6 yrs older than her sister Michelle and Michelle is two years younger than their brother David If the sum of their age

frosja888 [35]

You are told the ages of Karen and David in terms of Michelle's age.
Let m = Michelle's age.

Michelle's age = m
Karen's age = m + 6

Michelle is two years younger than David, so David is two years older than Michelle.

David's age = m + 2

Add the ages and get 62.

m + m + 6 + m + 2 = 62

3m + 8 = 62

3m = 54

m = 18

Michelle is 18 years old

Karen is 6 years older, so she is 24 years old.

David is 2 years older than Michelle, so he is 20 years old.

4 0

2 years ago

Help with 30 please. thanks.

Svet_ta [14]

Answer:

See Below.

Step-by-step explanation:

We have the equation:

$\displaystyle y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}$

And we want to show that:

$\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}$

Instead of differentiating directly, we can first square both sides:

$\displaystyle y^2 = 3e^{2x} -4x + 1$

We can find the first derivative through implicit differentiation:

$\displaystyle 2y \frac{dy}{dx} = 6e^{2x} -4$

Hence:

$\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}$

And we can find the second derivative by using the quotient rule:

$\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}$