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Agata [3.3K]
3 years ago
11

A snack company makes three batches of a nut mix using the recipe shown.

Mathematics
1 answer:
Aneli [31]3 years ago
4 0

Answer:

how much of each type of nut should be used in each batch.

1/3 of the mix is almonds

1/6 is pistachios

1/2 is cashews

the first batch is

P.1cup

A.2cup

C.?

Batch 2 is

P.?

A.2/3

C.1

the Third batch is

P.4/6

A.?

C.?

The answers are Batch 1:  3 cups cashews; Batch 2:  1/3 cup pistachios; Batch 3:  4/3 cups almonds and 2 cups cashews

Step-by-step explanation:

Let’s represent the total amount of mix with y

Batch 1

Since the amount of pistachios is 1/6 of the total and that is 1 cup which gives us

1/6y = 1

The next step is to multiply both sides by 6:

1/6y(6) = 1(6)

y = 6

We have 6 cups total.  1/2 of the mix is cashews which mean 1/2(6) = 3 cups is cashews.

Batch 2

Since the amount of almonds is 1/3 of the total and that is 2/3 of a cup which gives us

1/3y = 2/3

The next step is to multiply both sides by 3:

1/3y(3) = 2/3(3)

y = 6/3 = 2

There are 2 cups of mix total.

1/6 of the mix is pistachios; this gives us 1/6(2) = 2/6 = 1/3 cup pistachios.

Batch 3

Since the amount of pistachios is 1/6 of the total mix and that is 4/6 of a cup which means

1/6y = 4/6

The next step is to multiply both sides by 6:

1/6y(6) = 4/6(6)

y= 24/6 = 4

Since there are 4 cups of mix total, we have  

1/3 of the mix is almonds which gives us 1/3(4) = 4/3 cups almonds.  

1/2 of the mix is cashews which gives us 1/2(4) = 2 cups cashews.

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Answer:

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Step-by-step explanation:

Let,

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y be the number of tickets sold at the dance

According to given statement;

x+y=334      Eqn 1

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Multiplying Eqn 1 by 18

18(x+y=334)

18x+18y=6012      Eqn 3

Subtracting Eqn 3 from Eqn 2

(18x+24y)-(18x+18y)=7320-6012

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The authors of a paper concluded that more boys than girls listen to music at high volumes. This conclusion was based on data fr
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Answer:

Since the calculated value of z= 2.82  does not lie in the critical region  the null hypothesis is accepted and it is concluded that the sample data support the authors' conclusion that the proportion of the country's boys who listen to music at high volume is greater than this proportion for the country's girls.

The value of p is 0 .00233. The result is significant at p < 0.10.

Step-by-step explanation:

1) Let the null and alternate hypothesis be

H0:  μboys − μgirls > 0

against the claim

Ha: μboys − μgirls ≤ 0

2) The significance level is set at 0.01

3) The critical region is z  ≤  ± 1.28

4) The test statistic

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Here p1= 397/768= 0.5169  and p2= 331/745=0.4429

pc = 397+331/768+745

pc= 0.4811

qc= 1-pc= 1-0.4811=0.5188

5) Calculations

Z= p1-p2/ sqrt [pcqc( 1/n1+ 1/n2)]

z= 0.5169-0.4429/√ 0.4811*0.5188( 1/768+  1/745)

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6) Conclusion

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7)

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