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madreJ [45]
3 years ago
13

5. In the triangle ABC. M is the midpoint of [AB] and N is the midpoint of [CM].

Mathematics
1 answer:
sweet [91]3 years ago
8 0

Answer:

N(2,3)

Step-by-step explanation:

According to the Question,

  • Given that, In the triangle ABC. M is the midpoint of AB and N is the midpoint of CM And A(-1, 3), B(7-3) and C(1,6).
  • Thus, For coordinates of N. first We have to find the Coordinate of M(x,y). As Given M is the Midpoint of A(-1, 3) and B(7-3).

Thus, M(x,y) = (-1+7)/2 , (3-3)/2 ⇒ M(3,0)

  • Now, As Given, N(a,b) is the Midpoint Of C(1,6) and M(3,0).

Thus. N(a,b) = (1+3)/2 , (6+0)/2  ⇒ N(2,3)

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Answer:

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Step-by-step explanation:

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3 years ago
While sailing, Jacob is 150 feet from a lighthouse. The angle of elevation from his feet on the boat (at sea level) to the top o
Vlada [557]

Answer:

The height of the lighthouse is approximately 166.6 feet.

Step-by-step explanation:

Let the height of the lighthouse be represented by s, then;

Tan 48° = (opposite) ÷ (adjacent)

Tan 48° = s ÷ 150

⇒ s = 150 × Tan 48°

      = 150 × 1.1106

     = 166.59

s ≅ 166.6 feet

Therefore, the height of the lighthouse is approximately 166.6 feet.

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2 years ago
A very, very hungry guy goes to a fast food place and orders 2 chicken sandwiches
siniylev [52]

Answer:

Step-by-step explanation:

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6 0
3 years ago
henry is organizing textbooks on his bookshelf. he has a spanish textbook, a math textbook, and a history textbook. how many dif
Brums [2.3K]

Answer:

6

Step-by-step explanation:

S = Spanish book

M = Math book

H = History book

These are the different ways in which he can organize the book on his bookshelf.

SMH

SHM

MSH

MHS

HSM

HMS

There are 6 ways.

6 0
1 year ago
Further mathematics: Find the derivative of the function x^2 y + (xy)^3 +3x=0 at (-1 , 3)​
vesna_86 [32]

Answer:

3.

Step-by-step explanation:

Implicit differentiation:

x^2 y + (xy)^3 + 3x = 0

x^2 y + x^3y^3 + 3x = 0

Using the product rule:

2x* y + x^2*dy/dx + 3x^2 y^3 + x^3* (d(y^3)/dx) + 3 = 0

2xy + x^2 dy/dx + 3x^2 y^3 + x^3* 3y^2 dy/dx + 3 = 0

dy/dx(x^2 + 3y^2x^3) =  (-2xy - 3x^2y^3 - 3)

dy/dx=  (-2xy - 3x^2y^3 - 3) / (x^2 + 3y^2x^3)

At the point (-1, 3).

the derivative =  (6 - 81 - 3)/(1 -27)

= -78/-26

=  3.

8 0
2 years ago
Read 2 more answers
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