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loris [4]
3 years ago
12

Select three ratios that are equivalent to 4:3 Choose 3 correct answers

Mathematics
1 answer:
gregori [183]3 years ago
7 0

Answer:

8:6 & 12:9 & 16:12

Step-by-step explanation:

hope this help ☆

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The olive trees in an orchard produce 3,000 pounds of olives a year. It takes 20 pounds of olives to make 3 liters of olive oil.
AleksAgata [21]

Answer:

450L

Step-by-step explanation:

This is a ratio and proportion problem. First you need to determine the known ratio and the unknown ratio. In this case we have the known ratio:

\dfrac{20 lbs}{3L}

The unknown ratio in this case is:

\dfrac{3,000lbs}{xL}

So to do this, we just set up the proportion and solve for it:

\dfrac{20lbs}{3L}=\dfrac{3,000lbs}{xL}\\\\{20lbs}=\dfrac{3L\times3,000lbs}{xL}\\\\{xL}=\dfrac{3L\times3,000lbs}{20lbs}\\\\{xL}=\dfrac{9,000L}{20}\\\\xL = 450L

7 0
3 years ago
Which number(s) are 6 units from zero on a number line?<br><br> -6<br> 12<br> 6<br> 3
Amiraneli [1.4K]

Answer: 6 and -6


Step-by-step explanation:

6 Is the distance from zero, since distance cannot be negative, it does not matter if we go left or right on the number line, it will still be 6 units away from zero.

6 0
4 years ago
Let the (x; y) coordinates represent locations on the ground. The height h of
grigory [225]

The critical points of <em>h(x,y)</em> occur wherever its partial derivatives h_x and h_y vanish simultaneously. We have

h_x = 8-4y-8x = 0 \implies y=2-2x \\\\ h_y = 10-4x-12y^2 = 0 \implies 2x+6y^2=5

Substitute <em>y</em> in the second equation and solve for <em>x</em>, then for <em>y</em> :

2x+6(2-2x)^2=5 \\\\ 24x^2-46x+19=0 \\\\ \implies x=\dfrac{23\pm\sqrt{73}}{24}\text{ and }y=\dfrac{1\mp\sqrt{73}}{12}

This is to say there are two critical points,

(x,y)=\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\text{ and }(x,y)=\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)

To classify these critical points, we carry out the second partial derivative test. <em>h(x,y)</em> has Hessian

H(x,y) = \begin{bmatrix}h_{xx}&h_{xy}\\h_{yx}&h_{yy}\end{bmatrix} = \begin{bmatrix}-8&-4\\-4&-24y\end{bmatrix}

whose determinant is 192y-16. Now,

• if the Hessian determinant is negative at a given critical point, then you have a saddle point

• if both the determinant and h_{xx} are positive at the point, then it's a local minimum

• if the determinant is positive and h_{xx} is negative, then it's a local maximum

• otherwise the test fails

We have

\det\left(H\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\right) = -16\sqrt{73} < 0

while

\det\left(H\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)\right) = 16\sqrt{73}>0 \\\\ \text{ and } \\\\ h_{xx}\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-8 < 0

So, we end up with

h\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-\dfrac{4247+37\sqrt{73}}{72} \text{ (saddle point)}\\\\\text{ and }\\\\h\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)=-\dfrac{4247-37\sqrt{73}}{72} \text{ (local max)}

7 0
3 years ago
Explain how to use a net to find the surface area of a prism
r-ruslan [8.4K]

Answer:

use a net to fin surface area of a prism by multyplying 10 to the power of 50

Step-by-step explanation:

3 0
3 years ago
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lord [1]
The correct answer for 12 is B
6 0
4 years ago
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