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3 years ago

PART 3 PLZ ANSWER 32 POINTS

Mathematics

1 answer:

balandron [24]3 years ago

6 0

i think you can do this one : )

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If discriminant (b^2 -4ac>0) how many real solutions

MaRussiya [10]

Answer:

If Discriminant, $b^{2} -4ac >0$

Then it has Two Real Solutions.

Step-by-step explanation:

To Find:

If discriminant (b^2 -4ac>0) how many real solutions

Solution:

Consider a Quadratic Equation in General Form as

$ax^{2} +bx+c=0$

then,

$b^{2} -4ac$ is called as Discriminant.

So,

If Discriminant, $b^{2} -4ac >0$

Then it has Two Real Solutions.

If Discriminant, $b^{2} -4ac < 0$

Then it has Two Imaginary Solutions.

If Discriminant, $b^{2} -4ac=0$

Then it has Two Equal and Real Solutions.

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Answer:

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Step-by-step explanation:

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anastassius [24]

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