A. $250 b. $200 c. $235 d. $275 Please help!

1.What is the true density of water? 2.What variables change the density of water? 3. How does water go against the concept of "

artcher [175]

Answer:

1. A common unit of measurement for

water's density is gram per milliliter

(1 g/ml) or 1 gram per cubic

centimeter (1 g/cm3). Actually, the

exact density of water is not really 1

g/ml, but rather a bit less (very, very

little less), at 0.9998395 g/ml at 4.0°

Celsius (39.2° Fahrenheit).

2. Water density changes with

temperature and salinity. Density is

measured as mass (g) per unit of

volume (cm). Water is densest at

3.98°C and is least dense at 0°C

(freezing point). Water density

changes with temperature and

salinity.

3. When water is a liquid, the water

molecules are packed relatively

close together but can slide past

each other and move around freely

(as stated earlier, that makes it a

liquid). Pure water has a density of

1.000 g/cm3 at 4° C. As the

temperature increases or decreases

from 4° C, the density of water

decreases.

6 0

3 years ago

Read 2 more answers

Prove that |a| < b if and only if -b < a < b

asambeis [7]

Answer:

Since,

$|x|=\left\{\begin{matrix}x &\text{ if } x \geq 0 \\ -x &\text{ if } x < 0\end{matrix}\right.$

Here, the given equation is,

|a| < b

Case 1 : if a ≥ 0,

|a| < b ⇒ a < b

Case 2 : If a < 0,

|a| - b

( Since, when we multiply both sides of inequality by negative number then the sign of inequality is reversed. )

|a| < b ⇒ a - b ⇒ -b < a < b

Conversely,

If -b < a < b

⇒ a - b

⇒ a < b or -a < b

⇒ |a| < b

Hence, proved..

7 0

4 years ago

A school is planning an event to raise 1000 for charity. The cost of organizing the event is 200. The tickets are priced at 6 pe

alexdok [17]

Answer:

a) 1200

b) 150

Step-by-step explanation:

a) total revenue = target amount + expenses

... total revenue = 1000 + 200

... total revenue = 1200

b) total revenue = adult tickets × adult ticket price

... 1200 = adult tickets × 8 . . . . . . . . . . fill in the information you know

... 1200/8 = adult tickets = 150 . . . . . divide by 8

4 0

3 years ago

Read 2 more answers

Suppose that $p$ and $q$ are positive numbers for which \[\log_9 p = \log_{12} q = \log_{16} (p + q).\] what is the value of $q/

SVEN [57.7K]

Given $p,q>0$ and $\log_9p=\log_{12}q=\log_{16}(p+q)=x$ (say).

Then,

$p=9^x\\ q=12^x\\ p+q=16^x$

From the above 3 equations,

$\frac{q}{p} =(\frac{12}{9} )^x\\ \frac{q}{p} =(\frac{4}{3} )^x\\ \frac{p+q}{p} =(\frac{16}{9} )^x\\ \frac{p+q}{p} =(\frac{4}{3} )^{2x}\\$

From the equations, we get

$\frac{p+q}{p}=(\frac{q}{p})^2\\ 1+\frac{q}{p}=(\frac{q}{p})^2\\ (\frac{q}{p})^2-\frac{q}{p}-1=0\\ \frac{q}{p}=\frac{1 \pm \sqrt{5}}{2}$

Since $p,q>0$ , the negative value is rejected.

$\frac{q}{p}=\frac{1 + \sqrt{5}}{2}$

3 0

4 years ago

Last question of the day with 25 points.

pshichka [43]

Answer:

244 degrees

Step-by-step explanation:

Since one angle APE is 90 degrees, that means line segments AD and BE are perpendicular bisectors.

Since both segments go through the center, that means all the angles are central angles.

Since angle APE is 90 degrees, that also means that angle EPD is 90 degrees.

33k -9 = 90

33k = 99

k = 3

Since we know k we can substitute it to find angle CPD.

20 k + 4 = 20*3 + 4= 60+4= 64 degrees.

Central angles equal angles of arcs, so we can and angles APE, EPD, and DPC to find the measure of major arc CAD.

64+ 90 +90 = 244 degrees

3 0

3 years ago