A. $250<br> b. $200<br> c. $235<br> d. $275<br><br> Please help!

Someone please answer!

Alik [6]

Answer:

m=1/2

Step-by-step explanation:

y1= 1

y2=6

x1= -10

x2-0

m= slope

m= y2-y1/x2-x1

m=6-1/0 - - 10

m= 6-1/0+10

m=5/10

m=1/2

6 0

2 years ago

Find the square of each number

alexandr1967 [171]

There’s nothing here to solve

5 0

2 years ago

Can someone help me please

OleMash [197]

Answer:

<h3> $\boxed{ \bold{ \huge{ \boxed{ \sf{ {12.56 \: {mm}^{2} }}}}}}$ </h3>

Step-by-step explanation:

Given,

Radius ( r ) = 2 mm

pi ( π ) = 3.14

<u>Finding </u><u>the </u><u>area </u><u>of </u><u>circle </u><u>having </u><u>radius </u><u>of </u><u>2</u><u> </u><u>mm</u>

Area of circle $\sf{ = \pi \: {r}^{2} }$

plug the values

⇒ $\sf{3.14 \times {2}^{2} }$

Evaluate the power

⇒ $\sf{3.14 \times 4}$

Multiply the numbers

⇒ $\sf{12.56 \: {mm}^{2} }$

Hope I helped!

Best regards!!

4 0

2 years ago

Problema: Se guarda una moneda antigua en una caja cubica de tal forma que el contorno de la moneda toca las 4 paredes de la caj

nikdorinn [45]

Answer: 50.24 cm^2

Step-by-step explanation:

This can be translated to:

An old coin is kept in a cubic box in such a way that the outline of the coin touches the 4 walls of the box, if the base of the box has a perimeter of 24 cm. What is the area of the coin?

The fact that the coin touches the interior of the box means that the diameter of the coin is equal to the side lenght of the box.

The perimeter of the box is 24 cm, and the perimeter of a square is equal to:

P = 4*L

where L is the side lenght of the square.

24 cm = 4*L

L = 24cm/4 = 8cm

Now we know that the diameter of the coin is 8cm

Now, the area of a circle (the coin) is equal to:

A = 3.14*(d/2)^2

where d is the diameter, so we have:

A = 3.14*(4cm)^2 = 50.24 cm^2

3 0

2 years ago

Need this badly!!!!!!

prohojiy [21]

<h2>Hello!</h2>

The answer is:

The center of the circle is located on the point (-9,-2) and the radius is 6 units.

To solve the problem, we need to use the given equation which is in the general form.

We are given the circle:

$x^{2}+y^{2}+18x+4y+49=0$

We know that a circle can be written in the following form:

$(x-h)^{2}+(y-k)^{2}=r^{2}$

Where,

h is the x-coordinate of the center of the circle

k is the y-coordinate of the center of the circle

r is the radius of the circle.

So, to find the center and the radius, we need to perform the following steps:

- Moving the constant to the other side of the equation:

$x^{2}+y^{2}+18x+4y=-49$

- Grouping the terms:

$x^{2}+18x+y^{2}+4y=-49$

- Completing squares for both variables, we have:

We need to sum to each side of the equation the following term:

$(\frac{b}{2})^{2}$

Where, b, for this case, will the coefficients for both terms that have linear variables (x and y)

So, the variable "x", we have:

$x^{2} +18x$

Where,

$b=18$

Then,

$(\frac{18}{2})^{2}=(9)^{2}=81$

So, we need to add the number 81 to each side of the circle equation.

Now, for the variable "y", we have:

$y^{2} +4y$

Where,

$b=4$

$(\frac{4}{2})^{2}=(2)^{2}=4$

So, we need to add the number 4 to each side of the circle equation.

Therefore, we have:

$(x^{2}+18x+81)+(y^{2}+4y+4)=-49+81+4$

Then, factoring, we have that the expression will be:

$(x+9)^{2}+(y+2)^{2}=36$

- Writing the standard form of the circle:

Now, from the simplified expression (after factoring), we can find the equation of the circle in the standard form:

$(x+9)^{2}+(y+2)^{2}=36$

Is also equal to:

$(x-(-9))^{2}+(y-(-2))^{2}=36$

Where,

$h=-9\\k=-2\\r=\sqrt{36}=6$

Hence, the center of the circle is located on the point (-9,-2) and the radius is 6 units.

Have a nice day!

3 0

2 years ago

A. $250 b. $200 c. $235 d. $275 Please help!