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Dovator [93]
3 years ago
8

What is the mean of the following data values? 22, 37, 49, 15.92

Mathematics
2 answers:
Nonamiya [84]3 years ago
7 0

Answer:

30.98

Step-by-step explanation:

To solve for the mean/average of a set of numbers, you add them and divide by the number of numbers/data values.

(22+37+49+15.92)/4 = 123.92/4 = 30.98

Hope this helps and sorry if I made a mistake. :)

Natalija [7]3 years ago
5 0
The correct answer is 30.98

to find the mean in any data set you add all of the numbers together and then divide the sum by the total amount of numbers (in this data set it’s 4)
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A boat is pulled into a dock by a rope attached to the bow of the boat and passing through a pulley on the dock that is 1 m high
Agata [3.3K]

Answer:

dy/dt = 1.02 m/s

Step-by-step explanation:

First of all, let the distance of the dock above the bow of the boat be represented by x.

Also, let the distance of the boat from the dock be represented by y.

Let z represent the length of the rope.

Now, we can use pythagoras theorem to find a relationship between x, y and z since they form a right angle triangle where the vertical part is the dock, the base represents the water and the hypotenuse represents the rope.

Thus;

x² + y² = z²

Using implicit differentiation, we have;

2x(dx/dt) + 2y(dy/dt) = 2z(dz/dt)

We are given that the dock is 1 meter above the bow. Thus, x = 1

Also, the height is not changing and so dx/dt = 0

We are told the dock is 5 feet away from the boat. Thus, y = 5

dy/dt is is the speed we are looking for which is the rate at which the boat is approaching the dock.

We are not given the value of z but we can find it by using pythagoras theorem since we know the dock is 1 meter above the bow and the boat is 5 m away.

Thus;

z = √(1² + 5²)

z = √26

We are told the rope is being pulled in at the rate of 1 m/s. Thus; dz/dt = 1

Plugging all relevant values into the differentiation equation above gives;

2(1)(0) + 2(5)(dy/dt) = 2(√26)(1)

10(dy/dt) = 2√26

Divide both sides by 10 to get:

dy/dt = (√26)/5

dy/dt = 1.02 m/s

5 0
3 years ago
Pls help and answer quick!! <br><br> find x
siniylev [52]

hi

I Don't know

sorry

I will try to say next time

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3 years ago
Please show your work this question what made you come to the conclusion. Thank you
AveGali [126]

Answer:

B the range, the x- and y-intercept

Step-by-step explanation:

the domain stays the same : all values of x are possible out of the interval (-infinity, +infinity).

but the range changes, as for the original function y could only have positive values - even for negative x.

the new function has a first term (with b) that can get very small for negative x, and then a subtraction of 2 makes the result negative.

the y-intercept (x=0) of the original function is simply y=1, as b⁰=1.

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the original function has no x-intercept (y=0), as this would happen only for x = -infinity. and that is not a valid value.

the new function has an x-intercept, because the y-values (range) go from negative to positive numbers. any continuous function like this must therefore have an x-intercept (again, y = the function result = 0)

3 {b}^{x + 1}  = 2

{b}^{x + 1}  = 2 \div 3

log_{b}(2 \div 3)  = x + 1

x =  log_{b}(2 \div 3)  - 1

8 0
3 years ago
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