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3 years ago

What is the mean of the following data values? 22, 37, 49, 15.92

Mathematics

2 answers:

Nonamiya [84]3 years ago

7 0

Answer:

30.98

Step-by-step explanation:

To solve for the mean/average of a set of numbers, you add them and divide by the number of numbers/data values.

(22+37+49+15.92)/4 = 123.92/4 = 30.98

Hope this helps and sorry if I made a mistake. :)

Natalija [7]3 years ago

5 0

The correct answer is 30.98

to find the mean in any data set you add all of the numbers together and then divide the sum by the total amount of numbers (in this data set it’s 4)

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Please help 30 points and if I get correct answer i will brainiest them

WINSTONCH [101]

Answer:

9,-4

Step-by-step explanation:

-9×4=-36

Negative × Positive = Negative

8 0

3 years ago

Write an equation that you can use to solve for the height of the triangle (x). Notice that the perimeter is 48 feet.

MArishka [77]

A. 48 = 12 + 20 + x

If you use this equation then you can do 12 + 20 = 32 and then you can do 48 - 32 = 16 so x = 16

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3 years ago

2(n+5)=-2 <br><br> I need the steps

Eva8 [605]

Answer:

n = -6

Step-by-step explanation:

2 ( n + 5 ) = -2

First, solve the brackets.

2n + 10 = -2

Now take 10 to the right side.

2n + 10 -10 = -2 - 10

2n = -12

Then divide both sides by 2.

$\frac{2n}{2} =\frac{-12}{2}$

And now you'll the value of n.

n = ( -6 )

6 0

3 years ago

A botanist wishes to estimate the typical number of seeds for a certain fruit. She samples 48 specimens and counts the number of

baherus [9]

Answer: The open interval would be (31.4,42.5).

Step-by-step explanation:

Since we have given that

mean = 36.9

Standard deviation = 16.5

n = 48

At 98% confidence interval, z = 2.33

So, Interval would be

$\bar{x}\pm z\dfrac{\sigma}{\sqrt{n}}\\\\=36.9\pm 2.33\dfrac{16.5}{\sqrt{48}}\\\\=36.9\pm 5.549\\\\=(36.9-5.5,36.9+5.6\\\\=(31.4,42.5)$

Hence, the open interval would be (31.4,42.5).

5 0

3 years ago

Find the 64th term of the following arithmetic sequence.<br><br> 17, 26, 35, 44, ...

goblinko [34]

take the difference

26-17=9

35-26=9

the first term is 17

and the nth term is 64

use the formula

tn=a+(n-1) d

let a be 17

let n be 64

let d be 9

then you substitute

t64=17+(64-1)9

=17+(63)9

=17+567

=584

so the 64th term is 584.

8 0

3 years ago