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iVinArrow [24]
2 years ago
12

PLEASE HURRY AND EXPLAIN IT BECAUSE I HAVE TO SHOW MY WORK!!!

Mathematics
1 answer:
777dan777 [17]2 years ago
3 0

We found the answer of 4.5. I had her add another 1.5 which gave us the number 6 in the chart to show proof to her.

Step-by-step explanation:

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(1/3)^3 = ____?<br><br> Im just working in school cheating on khan acad lol
Alexus [3.1K]

Answer:

Step-by-step explanation:

The answer is 1/27

due to

(1/3)^3 = [(1)^3]/[3^3] =1/27

Best regards

3 0
3 years ago
If Mary pay $3695.20for principal and interest every month for 30 years on her $110,000 loan, how much interest will she pay ove
PilotLPTM [1.2K]

Answer:

  $1,220,200

Step-by-step explanation:

The total of Mary's payments is ...

  $3695.20/mo × 30 yr × 12 mo/yr = $1,330,200

The difference between this repayment amount and the value of her loan is the interest she pays:

  $1,330,200 -110,000 = $1,220,200 . . . total interest paid

_____

Mary's effective interest rate is about 40.31% per year--exorbitant by any standard.

6 0
2 years ago
Write the algebraic expression that is represented by the model
Salsk061 [2.6K]
3x+2y=5

Hop this helps
4 0
3 years ago
Read 2 more answers
According to a survey, high school girls average 100 text messages daily (The Boston Globe, April 21, 2010). Assume the populati
Ghella [55]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: number of daily text messages a high school girl sends.

This variable has a population standard deviation of 20 text messages.

A sample of 50 high school girls is taken.

The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;δ²/n)

This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:

Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)

a.

P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836

b.

P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)

P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328

I hope you have a SUPER day!

3 0
2 years ago
the ratio of sallys height is 7:8. if the sum of their heights is 90 inches. how tall are sally and jack?
pickupchik [31]

Answer:

Sally is 42 in. tall, and Jack is 48 in. tall.

Step-by-step explanation:

There are some words missing in the problem.

Perhaps the problem was meant to read:

"The ratio of Sally's height to Jack's height is 7:8. If the sum of their heights is 90 inches, how tall are Sally and Jack?"

Solution:

The ratio of the heights is 7:8.

Sally could measure 7 inches and Jack 8 inches, but then when you add the heights, 7 in. + 8 in. = 15 in. which is not 90 inches.

If you multiply both numbers in a ratio by the same number, the new numbers are still in the same ratio.

Multiply 7 and 8 by 2. You get 14 and 16. Maybe Sally is 14 in. tall and Jack is 16 in. tall. Add the heights, 14 in. + 16 in. = 30 in. This is also not 90 in.

We can keep on guessing what number to multiply by 7 and 8 by so their sum is 90, but we can use algebra to write an equation and not have to go through many guesses.

There is a number, x, that when you multiply 7 and 8 by x, the sum of the products is 90. We don't know what x is, but we can write an equation and solve for x.

The numbers in the ratio are 7x and 8x.

7x and 8x are still in the ratio 7:8.

Now we add the numbers 7x and 8x and set the sum equal to 90. Then we solve for x.

7x + 8x = 90

15x = 90

x = 6

We get x = 6. Now we know we need to multiply both 7 and 8 by 6 to get the heights we need.

7 in. * 6 = 42 in.

8 in. * 6 = 48 in.

Check: 42 in. + 48 in. = 90 in.

Answer: Sally is 42 in. tall, and Jack is 48 in. tall.

7 0
2 years ago
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