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3 years ago

Guys Idk this pls help 7th grade math simplify the expression

Mathematics

1 answer:

saveliy_v [14]3 years ago

7 0

Answer:

x^3 + y-3

Step-by-step explanation:

Hope this helps :]

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Cual ecuacion representa un ejemplo de la

Katarina [22]

Answer:

B) 6(x+2y) + 4 = 6x + 12 y + 4

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2 years ago

What is the approximate distance between the points (-3, -4) and (-8, 1) on a coordinate grid

tatyana61 [14]

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ -3 &,& -4~) 
% (c,d)
&&(~ -8 &,& 1~)
\end{array}\\\\\\ % distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{[-8-(-3)]^2+[1-(-4)]^2}\implies d=\sqrt{(-8+3)^2+(1+4)^2}
\\\\\\
d=\sqrt{25+25}\implies d=\sqrt{2\cdot 25}\implies d=\sqrt{2\cdot 5^2}\implies d=5\sqrt{2}$

4 0

2 years ago

Read 2 more answers

A slide that Baker Park has a height of 10 feet and is 15 feet long. How high are you off the ground when you are 6 feet down th

ss7ja [257]

Answer:

4 ft

Step-by-step explanation:

just look at the length of the slide and substract it.

10-6=4

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2 years ago

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In a G.P the difference between the 1st and 5th term is 150, and the difference between the

liubo4ka [24]

Answer:

Either $\displaystyle \frac{-1522}{\sqrt{41}}$ (approximately $-238$ ) or $\displaystyle \frac{1522}{\sqrt{41}}$ (approximately $238$ .)

Step-by-step explanation:

Let $a$ denote the first term of this geometric series, and let $r$ denote the common ratio of this geometric series.

The first five terms of this series would be:

$a$ ,
$a\cdot r$ ,
$a \cdot r^2$ ,
$a \cdot r^3$ ,
$a \cdot r^4$ .

First equation:

$a\, r^4 - a = 150$ .

Second equation:

$a\, r^3 - a\, r = 48$ .

Rewrite and simplify the first equation.

$\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}$ .

Therefore, the first equation becomes:

$a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150$ ..

Similarly, rewrite and simplify the second equation:

$\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}$ .

Therefore, the second equation becomes:

$a\, r\, \left(r^2 - 1\right) = 48$ .

Take the quotient between these two equations:

$\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}$ .

Simplify and solve for $r$ :

$\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}$ .

$8\, r^2 - 25\, r + 8 = 0$ .

Either $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ or $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ .

Assume that $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}$ .

Similarly, assume that $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = \frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}$ .

4 0

2 years ago

Please help someone

Romashka-Z-Leto [24]

Answer:

(-2, ∞)

Step-by-step explanation:

A function is "increasing" when its graph goes up to the right, the slope is positive. At a turning point (maximum or minimum), the function is neither increasing nor decreasing.

<h3>Increasing interval</h3>

The graph has a minimum at x = -2. To the left of that point, the graph goes up to the left, which is the same as down to the right (decreasing).

To the right of x = -2, the graph goes up to the right (increasing). It continues to increase for all values of x > 2. The interval where the function is increasing is said to be ...

-2 < x < ∞

The lack of "or equal to" tells you the interval is "open" and is delimited by parentheses in interval notation:

increasing; (-2, ∞)

6 0

1 year ago