The product of two rational numbers is always rational because (ac/bd) is the ratio of two integers, making it a rational number.
We need to prove that the product of two rational numbers is always rational. A rational number is a number that can be stated as the quotient or fraction of two integers : a numerator and a non-zero denominator.
Let us consider two rational numbers, a/b and c/d. The variables "a", "b", "c", and "d" all represent integers. The denominators "b" and "d" are non-zero. Let the product of these two rational numbers be represented by "P".
P = (a/b)×(c/d)
P = (a×c)/(b×d)
The numerator is again an integer. The denominator is also a non-zero integer. Hence, the product is a rational number.
learn more about of rational numbers here
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Answer:
(-2,-2)
Step-by-step explanation:
for question number 15...cordinated grid shows each equation...first equation is represented by straight line going upwards through +4 in y axis...(y=3x+4)...
point is....every point in this two lines represent a possible x and y value for each equation...and there is a point where these lines meet each other....in that point...x and y values are possible values for both equations.so answer is (-2,-2)...this cordination satisfy each pairs of equation...you can try using -2 for x in both equations and get -2 as the answer for y...that proves the point..try it for 16 quiz.good luck
Answer: -7twice
Step-by-step explanation:
This is a question on root of quadratic equation. The interpretation of the question
x² 14x + 49 is
x² + 14x + 49 = 0.meaning that we are to find two possible values for x that will make the expression equal 0.
We can use any of the methods earlier taught. For the purpose of this class, I am using factorization methods
x² + 14x + 49 = 0
Now, find the product of the first and the last terms, is
x² × 49 = 49ײ
Now find two terms such that their productbis 49x² and their sum equals 14x, the one in the middle.
We have several factors of 49x² but only one will give sum of 14x. Because of the time, I will only go straight to the required factors .
49x² = 7x × 7x and the sum gives 14x the middle terms..
Now we now replace the middle one by the factors and then factorize by grouping.
x² + 14x + 49 = 0
x² + 7x + 7x + 49 = 0
x(x + 7) + 7(x + 7) = 0
(x + 7)(x + 7). = 0
Now to find this value of x,
x + 7 = 0
x. = -7twice.
The root of the equation = -7twice.
