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3 years ago

Which values of x are solutions to the inequality? x<−200 Select each correct answer. x=−210 x=−120 x=−200 x=−102 x=−201

Mathematics

1 answer:

lesantik [10]3 years ago

7 0

Answer:

x = - 120 and x = - 102

Step-by-step explanation:

Consider the given values of x less than - 200

these are x = - 120 and x = - 102

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1. A rabbit can hop 6 feet in 2 seconds and 12 feet in 4 seconds. If the number of feet varies directly with the time the rabbit

kykrilka [37]

Answer: The rabbit is hopping at 3 feet/ sec in speed

Step-by-step explanation:

Step 1

Let the The number of feet of the rabbit be expressed as N

AND time rabbit spends hopping can be expressed as t

From the question, The number of feet varies directly with the time rabbit spends hopping can be expressed as

N α t

Let us introduce a constant of proportionality ,S which represents speed in this case, we now have that

N = St

STEP 2 -- SOLVING

If the rabbit hop 6 feet in 2 seconds, Then speed =

N = St

6= S X2

S = 6/ 2

S = 3

also

If the rabbit hop 12 feet in 4 seconds, Then speed =

N = St

12= S X 4

S = 12/ 4

S = 3

Also recall

that Speed = Distance / time

Pluging the values in the first case,

speed = 6 feet/ 2 secconds = 3 feet/ seconds

in the second case

Speed= 12 feet/ 4 second s= 3 feet/ secs.

5 0

3 years ago

Please Help!!<br> It's urgent :)

Paha777 [63]

Answer:

hope this helps

Step-by-step explanation:

For a.) I would do the simplist example possible and make all 3 angles equal. So you would divide 180° degrees by 3. This gives you 60° for each angle. That is still acute.

b.) complementary angles mean they add up to 90°

If one has to be greater than 45° you can so 68° and 22°.

c.) 100 - 10,10; 20,5; 50,2; 4,25

You can choose any pair for the length and width of the ones I put above. :)

d.) angle ABC can equal 32° and angle CBD can be 10°

8 0

3 years ago

Read 2 more answers

2) The two rectangles shown are similar.

Citrus2011 [14]

Answer:

$6\ cm$

Step-by-step explanation:

First Rectangle:

$length(l_1)=24\ cm\\\\Width(b_1)=9\ cm$

Second Rectangle:

$length(l_2)=16\ cm\\\\Let\ Width=b_2\ cm$

$Since\ these\ two\ rectangles\ are\ similar\\\\\frac{l_2}{l_1}=\frac{b_2}{b_1}\\\\\frac{16}{24}=\frac{b_2}{9}\\\\16\times 9=24\times b_2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ cross\ multiplication\\\\b_2=\frac{16\times 9}{24}\\\\b_2=6\ cm$