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Drupady [299]
3 years ago
14

The perimeter of the figure below is 41.6 in. Find the length of the missing side. (Note: diagram is NOT to scale)

Mathematics
1 answer:
Komok [63]3 years ago
5 0

Answer:

{ \tt{let \: that  \: unknown\: side \: be \: x}} \\ { \boxed{ \tt{perimeter = (8 \times side)}}} \\ 41.6 = (3.2 \times 2) + (5.9 \times 5) + x \\ x = 5.7 \:in \\ { \bf{answer : 5.7 \: inches}} \\  \\ { \underline{ \blue{ \tt{becker \: jnr}}}}

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A tessellation has 2 pairs of congruent angles around the point of intersection. The measure of each of one pair of congruent an
Over [174]

9514 1404 393

Answer:

  152°

Step-by-step explanation:

If two pairs of congruent angles total 360°, then the different angles must total 180°. The other angle measure is 180° -28° = 152°.

The measure of each angle in the other congruent pair is 152°.

8 0
3 years ago
20 feet of ribbon, cutting ribbon into 7 1/2 inches or 6 3/4 inch lengths to make bracelets. Write an algebraic expression that
IRINA_888 [86]

<u>ANSWER:  </u>

The algebraic expression for number of ribbons is \frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x} and the algebraic expression for length of ribbon is \frac{25 x}{3} \text { feet }

<u>SOLUTION: </u>

Given, 20 feet of ribbon, cutting ribbon into 7\frac{1}{2} inches or 6\frac{3}{4} inch lengths to make bracelets.

Let us convert the mixed fraction to improper fractions.

7 \frac{1}{2}=\frac{7 \times 2+1}{2}=\frac{15}{2} \text { and } 6 \frac{3}{4}=\frac{6 \times 4+3}{4}=\frac{27}{4}

Let, the length of bracelets can be made be “x”

First we have to remove the excess length of ribbon and then we have to divide the remaining with length of bracelet we want.

\text { number of ribbons }=\frac{\text { length of ribbon-excess ribbon.}}{\text {length of bracelet}}

\left.=\frac{20 \text { feet }-\left\{\frac{20 \text { feep }}{x}\right.}{x} \text { [we know that, }\{x\} \text { is fractional part of } x\right ]

So, the algebraic expression for number of ribbons is  \frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}

Now, let us find the algebraic expression for feet of ribbon to make 100 ribbons.

We have 100 bracelets of length x, then total length = 100 × x

length of ribbon = 100x inches

\begin{array}{l}{=100 \mathrm{x} \times \frac{1}{12} \text { feet }} \\\\ {=\frac{25 x}{3} \text { feet }}\end{array}

So, the algebraic expression for length of ribbon is \frac{25 x}{3} \text { feet }

Hence, the algebraic expression for number of ribbons is  \frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x} and the algebraic expression for length of ribbon is \frac{25 x}{3} \text { feet }

5 0
3 years ago
Find slope given the graph of a line on a grid
Alborosie
Slope is rise over run or Y2 - Y1 divided X2 - X1. The X's and Y's are your coordinate points. It doesn't matter which Y you put down first but remember to choose the X in the same place. Your coordinate points are (0, -1) and (-4, 2)

Your equation will be:

-1 - 2 / 0 - (-4)
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6 0
3 years ago
Katy is on a path, moving towards a bridge. The given table represents a function that describes Katy’s distance from the bridge
Sophie [7]

Answer:

D : Katy was 300 meters from the bridge, and it took her 6 minutes to reach the bridge.

Step-by-step explanation:

Recall that x represents the time walked

When you see the first entry on the table as: x=0, that means Katy is about to start her walk, and the value to the right which represents her distance from the bridge is 300 meters. So as her walk started she was 300 meters from the bridge.

Now look at the last entry pair at the bottom of the table: the value in the "x" column (that represents the number of minutes she walked) reads: 6, and the value to the right (next column) reads 0 (0 meters from the bridge)

This is telling us that Katy was at the bridge after 6 minutes of walk. So answer D is the correct answer representing the given table of time and distance values.

3 0
3 years ago
I’m so confused on how to do this
dimaraw [331]

Answer:

19

Step-by-step explanation:

First:  Recognize that (f o g)(x) is the "composition" of two functions, where g(x) serves as the input to f(x).  We are given f(x) = 2x+3 and g(x) = x+5.  You could find g(3) right now:  it is g(3) = 3+5 = 8.  Use this 8 as the input to f(x):  f(8) = 2(8)+3 = 19.

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